Answer:
1)
Null hypothesis H₀ : μ = 25,809
Alternative hypothesis H₁ : μ < 25,809
2) Test Statistic = -1.44
3) Conclusion:
The result is significant, there is sufficient evidence to support the bride’s hope at the 0.10 level of significance.
Step-by-step explanation:
Given the data in the question;
Sample mean x" = 24,638
sample size n = 46
standard deviation σ = 5531
level of significance ∝ = 0.10
NULL and ALTERNATIVE HYPOTHESIS
Null hypothesis H₀ : μ = 25,809
Alternative hypothesis H₁ : μ < 25,809
TEST STATISTICS
Z = (x"-μ) / σ√n
we substitute
Z = (24,638 - 25,809) / (5531/√46)
Z = -1171 / 815.5
Z = -1.44
Test Statistic = -1.44
Now, from normal z-table;
P-value = P( Z < -1.44 ) = 0.0749
P-value = 0.0749
Since P-value ( 0.0749 ) is less than level of significance ( 0.10 ), we reject H₀.
Conclusion:
The result is significant, there is sufficient evidence to support the bride’s hope at the 0.10 level of significance.
