Hey there
_________________
The correct answer is:
f(x+5)=(x+5)^2+3(x+5)-10
f(x+5)=x^2+10x+25+3x+15-10
f(x+5)=x^2+13x+30 and f(x+5)=x^2+kx+30 so
k=13
Now factor x^2+13x+30
Find j and k such that jk=ac=30 and j+k+b=13 so j and k are 10 and 3 so
(x+3)(x+10)
So the two zeros occur when x=-3 and -10 the smallest of which is:
x=-10
___________________________
Hope this helps you
Answer:
Step-by-step explanation:
In this case, h=2, k=-1, and r=5, so the equation is
There both in the decimal place
Answer:
-8y -56
Step-by-step explanation:
Hope this helps! If it does, please mark me brainliest. Thank you! ;)