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2 years ago

ANSWER ASAP FOR POINTS AND BRAINIEST!!

Mathematics

1 answer:

OverLord2011 [107]2 years ago

3 0

Answer:

(a) 552ft

(b) $220.8

Step-by-step explanation:

(a) TSA of cuboid = 2 (lb + bh + hl)

= 2 (12*8+8*9+9*12) = 2 ( 276) = 552 square feet.

(b) Cost of covering the box = $0.40 * 552 feet

= $220.8

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Given f(x)=21x+14, find f(5)

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$f(5)=21\cdot5+14=105+14=119$

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every 1/2 mile along a hiking path there is water fountain, every 1/4 mile there is a bench, and every 1/8 mile there is a marke

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3 years ago

Write the equation of the line that is parallel to y=-0.75x and that passes through the point (8,0)

Mila [183]

Equation of line parallel to y = -0.75x that passes through (8,0) is: y = -0.75x-6

Step-by-step explanation:

Given equation of line is:

$y=-0.75x$

The coefficient of x is the slope of the line so the slope of given line is: -0.75

As parallel lines have equal slopes so the required equation of line will have the same slope.

The slope-intercept form is:

$y = mx+b$

Putting the value of the slope

$y = -0.75x+b$

To find the value of b, putting the point in the equation

$0 = -0.75(8)+b\\0 = -6+b\\b = 6$

Putting the values of m and b, we get

$y = -0.75x-6$

Hence,

Equation of line parallel to y = -0.75x that passes through (8,0) is: y = -0.75x-6

Keywords: Equation of line, Slope-intercept form

Learn more about equation of line at:

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3 years ago

An angle measures 86.4° less than the measure of its supplementary angle. What is the measure of each angle?

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2 years ago

Match solutions and differential equations. Note: Each equation may have more than one solution. Select all that apply. (a) 7y''

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Answer:

a- $e^x,e^{-x}$

b- $x^{-2}$

c- $x^3$

Step-by-step explanation:

a.7 y''-7 y =0

Auxillary equation

$D^2-1=0$

$(D-1)(D+1)=0$

D=1,-1

Then , the solution of given differential equation

$y=e^x,y=e^{-x}$

2. $7x^2y''+14xy'-14 y=0$

Y= $y=x^3$

$y=3x^2$

$y''=6x$

Substitute in the given differential equation

$42x^3+42x^3-14x^3\neq 0$

Hence, $x^3$ is not a solution of given differential equation

$e^x,e^{-x}$ are also not a solution of given differential equation.

y= $x^{-2}$

$y'=-2x^{-3}$

$y''=6x^{-4}$

Substitute the values in the differential equation

$7x^2(6x^{-4})+14x(-2x^{-3})-14 x^{-2}$

= $42x^{-2}-28x^{-2}-14x^{-2}=0$

Hence, $x^{-2}$ is a solution of given differential equation.

c. $7x^2y''-42y=0$

$y=x^3$

$y'=3x^2$

$y''=6x$

Substitute the values in the differential equation

$42x^3-42x^3=0$

Hence, $x^3$ is a solution of given differential equation.

a- $e^x,e^{-x}$

b- $x^{-2}$

c- $x^3$

6 0

3 years ago

Read 2 more answers