Answer:
a.The classification error rate for records that are truly fraudulent: By increasing the cutoff value, the non-fraudulent records will go down and this increases the error rate.
Also, if the cutoff value is down, the fraudulent records will increase and this lowers the error rate
.b.The classification error rate for records that are truly non-fraudulent: By moving up the cutoff value, the fraudulent records will go down and this decreases the error rate.
Also, if the cutoff value is down, the non-fraudulent records will go down and this increases the error rate.
Answer:
3( n + 
)² - 
= 0
Step-by-step explanation:
3n² = 6 - 17n ⇔ 3n² + 17n - 6 = 0
3( n² + 2 × n + ( )² - ( )² - 2 ) = 0
3( n + )² - 3 × 
- 6 = 0
3( n + )² - = 0
Answer:
Step-by-step explanation:
4unity to the left
3unity down
0 is the correct answer bc you can’t have a negative sign under the radical bar
