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leva [86]
2 years ago
9

(-1,4) and ( 1, -1) Find the distance between each pair of points

Mathematics
1 answer:
Nikolay [14]2 years ago
8 0

Answer:

\sqrt{29}

Step-by-step explanation:

We are basically trying to find the hypotenuse of the triangle.

The distance between the x is 2, and the distance between the y is 5, which makes a length and a width.

Pythagrenum theorem: a^2+b^2=c^2

2^2 is 4, 5^2 is 25.

4+25 is 29.

The distance is \sqrt{29}.

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Is 4,800 milliliters equal, less than, or more than 4.2 liters?​
Andrews [41]

Answer:

less than

Step-by-step explanation:

because

1 l= 1000 ml

so 4.2 l= 4.2x1000

= 4200 l

so 4200<4800

8 0
3 years ago
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How is the diameter of a circle related to the distance around a circle
Anastasy [175]
The distance around a circle on the other hand is called circumference and half of the diameter or the midpoint th the circle border is called the radius of the circle.
5 0
3 years ago
How many triangles will be in the 5th set of triangles?
tia_tia [17]

Answer:

25.

Step-by-step explanation:

I am assuming you only mean the small triangles, not the composite ones.

The  second  triangle set has 3 triangles on bottom row and 1 on the top - total 4.

The 3rd triangle set has 5 triangles on the bottom , 3 on the next up and 1 on the top  - total  9

Following the pattern 4th set will have the number of triaNGLES

7 + 5 + 3 + 1 = 16.

So the 5th will have 9 + 7 + 5 + 3 +1 = 25 triangles.

6 0
3 years ago
In an arithmetic sequence, a17 = -40 and
Viktor [21]

Answer:

Tn = 2Tn-1 - Tn-2

Step-by-step explanation:

Before we can generate the recursive sequence, we need to find the nth term of the given sequence.

nth term of an AP is given as:

Tn = a+(n-1)d

If a17 = -40

T17 = a+(17-1)d = -40

a+16d = -40 ...(1)

If a28 = -73

T28 = a+(28-1)d = -73

a+27d = -73 ...(2)

Solving both equations simultaneously using elimination method.

Subtracting 1 from 2 we have:

27d - 16d = -73-(-40)

11d = -73+40

11d = -33

d = -3

Substituting d = -3 into 1

a+16(-3) = -40

a - 48 = -40

a = -40+48

a = 8

Given a = 8, d = -3, the nth term of the sequence will be

Tn = 8+(n-1) (-3)

Tn = 8+(-3n+3)

Tn = 8-3n+3

Tn = 11-3n

Given Tn = 11-3n and d = -3

Tn-1 = Tn - d... (3)

Tn-1 = 11-3n +3

Tn-1 = 14-3n

Tn-2 = Tn-2d...(4)

Tn-2 = 11-3n-2(-3)

Tn-2 = 11-3n+6

Tn-2 = 17-3n

From 3, d = Tn - Tn-1

From 4, d = (Tn - Tn-2)/2

Equating both common difference

(Tn - Tn-2)/2 = Tn - Tn-1

Tn - Tn-2 = 2(Tn - Tn-1)

Tn - Tn-2 = 2Tn-2Tn-1

2Tn-Tn = 2Tn-1 - Tn-2

Tn = 2Tn-1 - Tn-2

The recursive formula will be

Tn = 2Tn-1 - Tn-2

5 0
3 years ago
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Help please I give you a cookie
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K and j are adjacent
3 0
3 years ago
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