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3 years ago

(-1,4) and ( 1, -1) Find the distance between each pair of points

Mathematics

1 answer:

Nikolay [14]3 years ago

8 0

Answer:

$\sqrt{29}$

Step-by-step explanation:

We are basically trying to find the hypotenuse of the triangle.

The distance between the x is 2, and the distance between the y is 5, which makes a length and a width.

Pythagrenum theorem: a^2+b^2=c^2

2^2 is 4, 5^2 is 25.

4+25 is 29.

The distance is $\sqrt{29}$ .

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Solve the system of equations. 2.5y + 3x = 27 5x – 2.5y = 5 What equation is the result of adding the two equations? What is the

Nitella [24]

Answer:

The solution to this system is (4, 1/6).

Step-by-step explanation:

Please separate these two equations for clarity. I like to write them in column format:

2.5y + 3x = 27

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---------------------

8x = 32, and x = 4.

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3 years ago

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Galina-37 [17]

Answer: $\frac{2x}{15}$

This is the fraction 2x/15 which can be read as 2x over 15

=====================================================

Work Shown:

Divide $\frac{14x^2}{15}$ over $7x$ to get

$\frac{14x^2}{15} \div 7x = \frac{14x^2}{15} \div \frac{7x}{1}\\\\\frac{14x^2}{15} \div 7x = \frac{14x^2}{15} \times \frac{1}{7x}\\\\\frac{14x^2}{15} \div 7x = \frac{14x^2*1}{15*7x}\\\\\frac{14x^2}{15} \div 7x = \frac{7x*2x*1}{15*7x}\\\\\frac{14x^2}{15} \div 7x = \frac{2x}{15}\\\\$

You can think of it as dividing 14x^2 over 7x and that results in 2x. Then you place that result (2x) over 15 to end up with 2x/15

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Answer:

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