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Fofino [41]
3 years ago
14

WILL MARK BEST AND FIRST CORRECT ANSWER THE BRAINLIEST

Mathematics
1 answer:
Oduvanchick [21]3 years ago
7 0

Answer:

C I'm pretty sure yeah it's c

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35% of people who visit Pinewood state park take a hike on the Sunset Trail Loop it’s 175 visitors how does the trail last Satur
lara31 [8.8K]

Answer: they had 500 visitors

Step-by-step explanation:

8 0
3 years ago
225, 157, 144, 312, 281, 276, 166<br> What is the median of the data?
Lerok [7]
The answer is 281 see out the numbers in order from least to greatest then the middle number is the median
8 0
3 years ago
Find the equation of a line that is parallel to the line -3x+2y=10 and goes through the point (0,7).
Delvig [45]

Answer:

  3x -2y = -14

Step-by-step explanation:

The parallel line will have a new constant that can be found by substituting the given point for x and y.

  -3x +2y = -3(0) +2(7) = 14

An equation for the parallel line is ...

  -3x +2y = 14

__

In standard form, the leading coefficient is positive, so the standard form equation is ...

  3x -2y = -14

6 0
3 years ago
The clock has a diameter of 18 inches. At 8 o'clock, what is the area of the sector formed by the two hands of the clock? Round
Drupady [299]

Answer:

The area of the sector is 84.8 in.² to the nearest tenth

Step-by-step explanation:

∵ the clock is a circle

∴ The measure of angles between each two hours = 360° ÷ 12 = 30°

∵ At 8 o'clock the hour hand pointed on 8 and the minute hand pointed on 12

∴ There are 4 angles between the two hands

∴ The central angle subtended by the arc = 4 × 30° = 120°

∵ The Area of the sector = \frac{x}{360} \pi r^{2} where x is the central angle subtended by this arc

∴ Area sector = \frac{120}{360} × π × (18/2)²

∴ Area sector = \frac{1}{3} × π ×81 = 27π = 84.8 in² to the nearest tenth

8 0
3 years ago
Find the average value of the function on the given interval.<br> f(x)=(2x-1)1/2; [1,13]
Leni [432]

Answer:

The average value of the function on the given interval 6.5.

Step-by-step explanation:

Consider the given function is

f(x)=\dfrac{2x-1}{2}

We need to find the average value of the function on the given interval [1,13].

f(x)=\dfrac{2x}{2}-\dfrac{1}{2}

f(x)=x-0.5

The average value of the function f(x) on [a,b] is

Average=\dfrac{1}{b-a}\int\limits^b_a {f(x)} \, dx

Average value of the function on the given interval [1,13] is

Average=\dfrac{1}{13-1}\int\limits^{13}_{1} {x-0.5} \, dx

Average=\dfrac{1}{12}[\dfrac{x^2}{2}-0.5x]^{13}_{1}

Average=\dfrac{1}{12}[\dfrac{(13)^2}{2}-0.5(13)-(\dfrac{(1)^2}{2}-0.5(1))]

Average=\dfrac{1}{12}[78-0]

Average=6.5

Therefore, the average value of the function on the given interval 6.5.

6 0
3 years ago
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