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stich3 [128]
3 years ago
6

Im not using Brainly for my account how do i Remove it

Computers and Technology
2 answers:
jeyben [28]3 years ago
5 0
Log in to your account.
Visit your profile settings.
In the Privacy section, click the “Delete Account” button.
Alik [6]3 years ago
4 0

Answer:

Explanation:

The option to delete your account can be found in your Profile Settings under Privacy. Click on the box labelled I want to delete my account, and the request will be sent for the account to be deleted.

(hope this helps can i plz have brainlist :D hehe)

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The mode is least appropriate for:___________
bazaltina [42]

Answer:

Your question seems incomplete

Explanation:

7 0
2 years ago
Consider the following method, remDups, which is intended to remove duplicate consecutive elements from nums, an ArrayList of in
MAXImum [283]

Answer:

B. {1, 2, 2, 3, 3, 4, 5}

Explanation:

Given

The above code segment

Required

Determine which list does not work

The list that didn't work is B.\ \{1, 2, 2, 3, 3, 4, 5\}

Considering options (A) to (E), we notice that only list B has consecutive duplicate numbers i.e. 2,2 and 3,3

All other list do not have consecutive duplicate numbers

Option B can be represented as:

nums[0] = 1

nums[1] = 2

nums[2] = 2

nums[3] = 3

nums[4] = 3

nums[5] = 4

nums[6] = 5

if (nums.get(j).equals(nums.get(j + 1)))

The above if condition checks for duplicate numbers.

In (B), when the elements at index 1 and 2 (i.e. 2 and 2) are compared, one of the 2's is removed and the Arraylist becomes:

nums[0] = 1

nums[1] = 2

nums[2] = 3

nums[3] = 3

nums[4] = 4

nums[5] = 5

The next comparison is: index 3 and 4. Meaning that comparison of index 2 and 3 has been skipped.

<em>This is so because of the way the if statement is constructed.</em>

3 0
3 years ago
Tim has an old server computer that his company uses as a backup. One of the hard drives has gone bad and needs to be replaced.
dimaraw [331]

Answer:

SCSI.

Explanation:

It is a set of ANSI-developed simultaneous interface requirements for connecting scanners, drives, printers, and many other devices to systems.

Although when Tim has such an outdated network system which is used as a backup by his corporation. Then hard drive may have gone wrong and required replacement. The connector used by the hard disk drive is not something he has ever seen before, but he upload photos of that on the community board of the organization to aid determine what kind of hard disk drive they will also have to order.

So, according to the following scenario he required SCSI cable.

4 0
3 years ago
A​ client-server application that requires nothing more than a browser is called​ ________.
goblinko [34]
Hello  <span>Tacobell5401</span>

 Answer: A​ client-server application that requires nothing more than a browser is called​  thin-client application


Hope this helps
-Chris
3 0
3 years ago
Read 2 more answers
Given a string variable string 's;', implement a tokenizer to identify the unique tokens contained in this string, identify all
Flauer [41]

Answer:

#include <iostream>

#include <string>

#include <vector>

#include <cctype>

#include <algorithm>

using namespace std;

void matrixInit( vector< vector<int> >& matrix, int numRows, int numCols);

struct TokenFreq{

string token;

int freq;

};

string spaces(string& istr, string& newstr);

void printVector(vector<TokenFreq> & tfVec);

void getTokenFreqVec( string& istr, vector<TokenFreq> & tfVecVec);

void selectionSort( vector<TokenFreq> & tokFreqVector );  

void insertionSort( vector<TokenFreq> & tokFreqVector );

//main

int main(int argc, const char * argv[]) {

 

vector<vector<int> > matrix;

matrixInit(matrix, 3, 4);

 

string ostr1 = " I do keep the main points straight in my head most of the time, and I do know where to find the details when I need them. by Bjarne Stroustrup";

string ostr2 = " ";

string ostr3 = "Your time is limited, so don’t waste it living someone else’s life.Stay Hungry. Stay Foolish.";

//string ostr = ostr2;

string istr;

 

cout << "Enter the text: ";

getline(cin, istr);

vector<TokenFreq> tfVec;

getTokenFreqVec(istr, tfVec);

selectionSort(tfVec);

insertionSort(tfVec);

return 0;

}

//-----

void selectionSort( vector<TokenFreq> & tokFreqVector ){

TokenFreq temp;

int min;

 

for( int i = 0; i < int(tokFreqVector.size()-1); i++){

min = i;

for (int j = i+1; j <int(tokFreqVector.size()); j++){

if (tokFreqVector[j].freq < tokFreqVector[min].freq)

min = j;

}

if(min!=i)

{

temp = tokFreqVector[i];

tokFreqVector[i] = tokFreqVector[min];

tokFreqVector[min] = temp;

}

}

cout<<"-----selectionSort------------------"<<endl;

printVector(tokFreqVector);

}

void insertionSort( vector<TokenFreq> & tokFreqVector ){

TokenFreq temp;

int max;

 

for( int i = 0; i < int(tokFreqVector.size()-1); i++){

max = i;

for (int j = i+1; j < int(tokFreqVector.size()); j++){

if (tokFreqVector[j].freq > tokFreqVector[max].freq)

max = j;

}

if(max!=i)

{

temp = tokFreqVector[i];

tokFreqVector[i] = tokFreqVector[max];

tokFreqVector[max] = temp;

}

}

cout<<"-----insertionsort------------------"<<endl;

printVector(tokFreqVector);

}

string spaces(string& istr, string & newstr){

int j;

//Check double space and create new string with lowercase

for (int i = 0; i < int(istr.length()); ++i){

istr[i] = tolower(istr[i]);

if (isspace(istr[i])){

//check double space again

j = i+1;

while(true){

if (istr[j] == '\342') istr[j]=' ';

if (istr[j] == '\200') istr[j]=' ';

if (istr[j] == '\224') istr[j]=' ';

if(isspace(istr[j])) j++;

else break;

}

i=j-1;

newstr = newstr + istr[i];

}else

newstr = newstr + istr[i];

}

return newstr;

}

void getTokenFreqVec( string& istr, vector<TokenFreq> & tfVec){

string newstr;

int curr_beg = 0;

int curr_end = 0;

string word;

bool check = false;

int index=0;

 

//call func spaces to get new string

newstr = spaces(istr, newstr);

//cout << newstr << endl;

//cout << endl;

//cout << newstr << "||" << endl;

string tempstr = newstr;

 

if(newstr != " "){

tfVec.push_back(TokenFreq());

}

for (int i = 0; i < int(newstr.length()); ++i){

if(isspace(newstr[i])){

check = false;

 

curr_end = i;

word = tempstr.substr(curr_beg, curr_end - curr_beg);

curr_beg = i + 1;

 

for (int j = 0; j < int(tfVec.size()); j++){

if (tfVec[j].token == word){

tfVec[j].freq++;

check = true;

 

break;

}

}//end-for;

if (check == false && i!=(int(newstr.length())-1)){

//cout <<"**"<< word <<"**"<<word.length()<< endl;

tfVec[index].token=word;

tfVec[index].freq=1;

index++;

tfVec.push_back(TokenFreq());

}

word = "";

//add last value

}

}//end-for

 

if(!isspace(newstr[int(newstr.length())-1])){

word = tempstr.substr(curr_beg, curr_end - (int(newstr.length())-1));

tfVec[index].token=word;

tfVec[index].freq=1;

//tfVec.push_back(TokenFreq());

}

 

printVector(tfVec);

}

void printVector(vector<TokenFreq> & tfVec){

 

cout << "size= {" << tfVec.size() << endl;

for (int i = 0; i < int(tfVec.size()); i++){

cout << " [" << i << "] = (token = \""<< tfVec[i].token <<"\", freq = " << tfVec[i].freq << ")" << endl;

//cout << tfVec[i].token<<endl;;

}

cout << endl;

}

void matrixInit( vector< vector<int> >& matrix, int numRows, int numCols){

int i;

int j;

matrix.resize(numRows, vector<int>(numCols) );

for(i = 0; i< numRows; i++ ){

for(j = 0; j < numCols; j++ )

matrix[i][j] = i*j;

}

 

cout << "size of matrix is: " << numRows << "x" << numCols << endl;

for (i = 0; i < numRows; i++){

for (j = 0; j < numCols; j++){

cout<< "matrix[" << i << "][" << i << "]=" << matrix[i][j] << endl;

}

}

cout << endl;

}

Explanation:

3 0
3 years ago
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