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solniwko [45]
3 years ago
6

What stores all software and files on your computer and reads and writes data onto a spinning magnetic or optical disk?

Computers and Technology
1 answer:
stiv31 [10]3 years ago
8 0

Answer:

Depends. could be an external opticial drive, a scuzi drive, a real to real tape system, or just a simple electromagnetic hard drive with speeds of 1000 rpm or more

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Given the following schedule, show the locks that will occur and the subsequent schedule. Assume that strict 2PL is in effect, w
Alexxandr [17]

Answer:

see explaination

Explanation:

Please kindly check attachment for the step by step solution of the given problem

4 0
3 years ago
Which two keys on the keyboard allow an access user to move the insertion point to the next field to the right in datasheet view
Mashcka [7]
Hey there!

In Microsoft Access, you can click the Tab key then the Enter key on your keyboard to establish a new insertion point directly to the right of your current insertion point when entering data in datasheet view. 

Hope this helped you out! :-)
4 0
3 years ago
True or False. A Windows Server 2016 that was installed in Desktop Experience mode can be converted to Server Core mode.
9966 [12]

When we install the Windows Server 2016 in Desktop Experience mode we cannot change it to Server Core mode. To change it we must uninstall it and reinstall it changing the mode (False).

<h3>What is Windows Server?</h3>

Windows Server is the name of a line of products created and marketed by the Microsoft Corporation software company.

One of its products is Windows Server 2016, this server was characterized by having two modes that were:

  • Desktop Experience
  • Server Core

However, it had the difficulty that the user could not switch between the two modes but had to uninstall and install the mode he wanted to use.

Learn more about Windows Server in: brainly.com/question/9426216

8 0
3 years ago
What is the output for the following program?
Lelu [443]

Answer:

Output:

15

20

25

Explanation:

In first iteration value of num is 10. Condition is checked 10 is less than 21 so value of num is incremented by 5 and value 15 is printed than again condition is checked 15<21 so value of num is incremented again and 20 is printed. Again condition is checked 20<21. So 25 is printed. Then 4th time when condition is checked vakue of num is 25 and while loop condition becomes false because 25 is not less than 21 and program is terminated here.

6 0
2 years ago
1. Print out the string length of s1 2. Loop through characters in s2 with charAt() and display reversed string 3. Compare s2, s
konstantin123 [22]

Answer:

See explaination

Explanation:

public class StringLab9 {

public static void main(String args[]) {

char charArray[] = { 'C', 'O', 'S', 'C', ' ', '3', '3', '1', '7', ' ', 'O', 'O', ' ', 'C', 'l', 'a', 's', 's' };

String s1 = new String("Objected oriented programming language!");

String s2 = "COSC 3317 OO class class";

String s3 = new String(charArray);

// To do 1: print out the string length of s1

System.out.println(s1.length());

// To do 2: loop through characters in s2 with charAt and display reversed

// string

for (int i = s2.length() - 1; i >= 0; --i)

System.out.print(s2.charAt(i));

System.out.println();

// To do 3: compare s2, s3 with compareTo(), print out which string (s2 or s3)

// is

// greater than which string (s2 or s3), or equal, print the result out

if (s2.compareTo(s3) == 0)

System.out.println("They are equal");

else if (s2.compareTo(s3) > 0)

System.out.println("s2 is greater");

else

System.out.println("s3 is greater");

// To do 4: Use the regionMatches to compare s2 and s3 with case sensitivity of

// the first 8 characters.

// and print out the result (match or not) .

if (s2.substring(0, 8).compareTo(s3.substring(0, 8)) == 0)

System.out.println("They matched");

else

System.out.println("They DONT match");

// To do 5: Find the location of the first character 'g' in s1, print it out

int i;

for (i = 0; i < s2.length(); ++i)

if(s2.charAt(i)=='g')

break;

System.out.println("'g' is present at index " + i);

// To do 6: Find the last location of the substring "class" from s2, print it

// out

int index = 0, ans = 0;

String test = s2;

while (index != -1) {

ans = ans + index;

index = test.indexOf("class");

test = test.substring(index + 1, test.length());

}

System.out.println("Last location of class in s2 is: " + (ans + 1));

// To do 7: Extract a substring from index 4 up to, but not including 8 from

// s3, print it out

System.out.println(s3.substring(4, 8));

} // end main

} // end class StringLab9

7 0
3 years ago
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