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melisa1 [442]
2 years ago
10

Researchers wanted to see which species of lizard (A, B, or C) is most likely to survive a bacterial infection. So they infected

a total of 38 lizards and recorded how many survived after 48 hours. Of the 15 species B lizards, 40% survived. For those that were species C, one more survived than died. And of the 24 lizards that died, one-third of them were species A.
a. Create a contingency table to display this data.

b. What proportion of these lizards in this study were either species A or B?

c. What is the probability that a species C lizard in this study did not survive?
Mathematics
1 answer:
Slav-nsk [51]2 years ago
7 0

Answer:

A) attached below

B) 0.61

C) 0.47

Step-by-step explanation:

Given data:

Total number of lizards infected = 38

Of the 15 species B lizards 40% survived

For specie C one more survived than died

Out of the 24 lizards that died 1/3 were species A

<u>A) contingency table </u>

attached below

<u>B) Determine the proportion of these lizards in this study that were either specie A or Specie B </u>

P ( A or B ) = ( 8 + 15 ) / 38 = 0.605 ≈ 0.61

<u>C) determine the probability that specie C lizard did not study </u>

P ( not surviving  | C ) = 7 / 15 = 0.466 ≈ 0.47

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