Can someone help me with questions 56
2 answers:
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1) Change radical forms to fractional exponents using the rule:
The n<span>th root of "</span>a number" = "that number" raised to the<span> reciprocal of n.
For example </span>![\sqrt[n]{3} = 3^{ \frac{1}{n} }](https://tex.z-dn.net/?f=%20%5Csqrt%5Bn%5D%7B3%7D%20%3D%20%20%203%5E%7B%20%5Cfrac%7B1%7D%7Bn%7D%20%7D)
.
The square root of 3 (
) = 3 to the one-half power (
).
The 5th root of 3 (![\sqrt[5]{3}](https://tex.z-dn.net/?f=%20%5Csqrt%5B5%5D%7B3%7D%20)
) = 3 to the one-fifth power (
).
2) Now use the product of powers exponent rule to simplify:
This rule says
. When two expressions with the same base (a, in this example) are multiplied, you
can add their exponents while keeping the same base.
You now have
. These two expressions have the same base, 3. That means you can add their exponents:
3) You can leave it in the form
or change it back into a radical ![\sqrt[10]{3^7}](https://tex.z-dn.net/?f=%20%5Csqrt%5B10%5D%7B3%5E7%7D%20)
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Answer: or
The n<span>th root of "</span>a number" = "that number" raised to the<span> reciprocal of n.
For example </span>
The square root of 3 (
The 5th root of 3 (
2) Now use the product of powers exponent rule to simplify:
This rule says
You now have
3) You can leave it in the form
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Answer:
Answer: The required solution is
Step-by-step explanation: We are given to solve the following differential equation :
Let us consider that
be an auxiliary solution of equation (i).
Then, we have
Substituting these values in equation (i), we get
So, the general solution of the given equation is
Differentiating with respect to t, we get
According to the given conditions, we have
and
Thus, the required solution is