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2 years ago

6

PLEASE HELP MEEE ITS DUE IN 30 MINUTES!

2 answers:

ArbitrLikvidat [17]2 years ago

7 0

Answer:

(suprisingly easy) 6x3x4=72 in.

Step-by-step explanation:

luda_lava [24]2 years ago

4 0

Answer:

look for the formular of volume

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Anna baked 3 batches of cookies with cookies in each bath she then ate 8 cookies How many cookies does Anna have left? Write you

Marizza181 [45]

Answer: C= 3x -8

C is the amount of cookies left. X is he number in each batch.

Step-by-step explanation:

If she made the cookies in the bath, they could be very soggy and difficult to count!

5 0

2 years ago

Find the Value of k that will make the function f(x) continuous everywhere.

cricket20 [7]

well, if that function f(x) were to be continuos on all subfunctions, that means that whatever value 7x + k has when x = 2, meets or matches the value that kx² - 6 has when x = 2 as well, so then 7x + k = kx² - 6 when f(2)

$f(x)= \begin{cases} 7x+k,&x\leqslant 2\\ kx^2-6&x > 2 \end{cases}\qquad \qquad f(2)= \begin{cases} 7(2)+k,&x\leqslant 2\\ k(2)^2-6&x > 2 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ 7(2)+k~~ = ~~k(2)^2-6\implies 14+k~~ = ~~4k-6 \\\\\\ 14~~ = ~~3k-6\implies 20~~ = ~~3k\implies \cfrac{20}{3}=k$

6 0

1 year ago

Please do 9,10,11,12 fast please

MAVERICK [17]

Answer:

9) 1,2,3,6,9,18,27,54

10) 1, 2, 4, 5, 10, 20, 25, 50, 100

11) 1 , 3 , 5 , 15 , 25 and 75

12) 1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 20, 24, 30, 40, 60 and 120

7 0

2 years ago

The manager of a fleet of automobiles is testing two brands of radial tires and assigns one tire of each brand at random to the

Darya [45]

Answer:

Brand 1 Brand 2 Difference

37734 35202 2532

45299 41635 3664

36240 35500 740

32100 31950 150

37210 38015 −805

48360 47800 560

38200 37810 390

33500 33215 285

Sum of difference = 2532+ 3664+740+150 −805+ 560 +390 +285 = 7516

Mean = $d=\frac{7516}{8}$

Mean = $d=939.5$

a) d= 939.5

$\text{Sample Standard deviation, s} = \sqrt{\dfrac{(x-\bar{x})^2}{n-1}}$

$=\sqrt{\dfrac{(2532-939.5)^2+(3664-939.5)^2+(740-939.5)^2 ...+(285-939.5)^2}{8-1}}$

=1441.21

b)SD= 1441.21

c)Calculate a 99% two-sided confidence interval on the difference in mean life.

confidence level =99%

significance level =α= 0.01

Degree of freedom = n-1 = 8-1 =7

So, $t_{\frac{\alpha}{2}}=3.499$

Formula for confidence interval $= \left( \bar{X} \pm t_{\frac{\alpha}{2}} \times \frac{s}{\sqrt{n}} \right)$

Substitute the values

confidence interval $= 939.5 \pm 3.499 \times \frac{1441.21}{\sqrt{8}} \right)$

confidence interval $= 939.5 - 3.499 \times \frac{1441.21}{\sqrt{8}} \right)$ to $= 939.5 + 3.499 \times \frac{1441.21}{\sqrt{8}} \right)$

Confidence interval $−843.396\$ to $2722.396$

8 0

2 years ago

Which of the following equations has only one solution?

Daniel [21]

X^2-6x+9=0 has only one solution
Hope this helps

4 0

2 years ago

Read 2 more answers