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3 years ago

*15. Ana joins a gym that charges a $25 annual fee, plus $10 per month?

Mathematics

1 answer:

Nataliya [291]3 years ago

8 0

Answer:

C. 12 months

Step-by-step explanation:

145-25= 120

120/10= 12

she pays for 12 months

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A box contains a collection of triangular and square tiles. There are 2525 tiles in the box, containing 8484 edges total. How ma

AnnyKZ [126]

Let us consider the number of edges = x
we know that a triangle will have 3 edges and a square will have 4 edges. Using this details we can form an equation.
3x + 4x = 8484
7x = 8484
x = 8484/7
= 1212
Then
Number of square tiles = 1212/4
= 303
So there are 303 square tiles in the box. I hope the procedure is clear enough for your understanding. You can always use this method for solving similar problems.

5 0

3 years ago

What do the difference between the adjacent angle and opposite angle

PtichkaEL [24]

Answer:

The difference between the adjacent angle and the opposite angle is that for the adjacent side is the side next to the reference angle, and for the opposite side is the side directly across from the reference angle.

Hope this helped!

Have a supercalifragilisticexpialidocious day!

7 0

3 years ago

Which expressions are equivalent to 3x+3(x+y)?

storchak [24]

Answer: 6x+3y

Step-by-step explanation:

3x+3(x+y)= 3x+3x+3y=6x+3y

6 0

3 years ago

Photography World has a portrait special. A three-pose portrait package has a sitting fee of $35, and a six-pose package has a s

ki77a [65]

We know that a three-pose portrait package has a sitting fee of $35 and <span> a six-pose package has a sitting fee of $60. The total amount they collect is $690.

</span> $\text{Therefore, the equation can be}$ $35x + 60y = 690$

6 0

3 years ago

I need to find the greatest common factor of <img src="https://tex.z-dn.net/?f=40s%5E3t%5E5" id="TexFormula1" title="40s^3t^5" a

solong [7]

Answer:

$\large\boxed{GCF(40s^3t^5,\ 2s^4t^4,\ 14s^6t^6)=2s^3t^4}$

Step-by-step explanation:

$40s^3t^5=\boxed2\cdot2\cdot2\cdot5\cdot \boxed{s\cdot s\cdot s}\cdot \boxed{t\cdot t\cdot t\cdot t}\cdot t\\\\2s^4t^4=\boxed2\cdot \boxed{s\cdot s\cdot s}\cdot s\cdot \boxed{t\cdot t\cdot t\cdot t}\\\\14s^6t^6=\boxed2\cdot7\cdot \boxed{s\cdot s\cdot s}\cdot s\cdot s\cdot s\cdot \boxed{t\cdot t\cdot t\cdot t}\cdot t\cdot t\\\\GCF(40s^3t^5,\ 2s^4t^4,\ 14s^6t^6)=\boxed2\cdot \boxed{s\cdot s\cdot s}\cdot\boxed{t\cdot t\cdot t\cdot t}=2s^3t^4$

7 0

3 years ago