Answer:
We conclude that The point (-2, 3) satisfies the equation y = -x+1.
Hence, option B i.e. y = -x+1 is one of the equations of a system of two linear equations.
Step-by-step explanation:
Given
<u>Checking option A</u>
Given the equation
y = 3x-2
substitute x = -2 and y = 3
3 = 3(-2) - 2
3 = -6 - 2
3 = -8
FALSE!
L.H.S ≠ R.H.S
Thus,
The point (-2, 3) does not satisfy the equation y = 3x-2.
<u>Checking option B</u>
Given the equation
y = -x+1
substitute x = -2 and y = 3
3 = -(-2)+1
3 = 2+1
3 = 3
TRUE!
L.H.S = R.H.S
Thus,
The point (-2, 3) satisfies the equation y = -x+1.
<u>Checking option C</u>
Given the equation
y=x-1
substitute x = -2 and y = 3
3 = -2-1
3 = -3
FALSE!
L.H.S ≠ R.H.S
Thus,
The point (-2, 3) does not satisfy the equation y=x-1.
<u>Checking option D</u>
Given the equation
y=2x+3
substitute x = -2 and y = 3
3 = 2(-2)+3
3 = -4+3
3 = -1
FALSE!
L.H.S ≠ R.H.S
Thus,
The point (-2, 3) does not satisfy the equation y=2x+3.
Conclusion:
Thus, we conclude that The point (-2, 3) satisfies the equation y = -x+1.
Hence, option B i.e. y = -x+1 is one of the equations of a system of two linear equations.
