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Over [174]
3 years ago
9

If each quadrilateral below is a square, find the missing measures. please help :(

Mathematics
1 answer:
Airida [17]3 years ago
4 0
Vu=15 su=square root 450 TV= square root 450 SW= squareroot 450/2
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the number of girls on the school's basketball team decreased by 20% this year. if there were 25 girls on the team last year. ho
Harman [31]

Answer:

Step-by-step explanation:

okay so to get 10% of 20 you just move the decimal to the right one so 25.0 would become 2.5 then to find 20% of that you multiply by 2 so 2.5 x 2 = 5 so that means the team lost 5 girls. 25-5=20 therefor there are 20 players on the team this year

4 0
3 years ago
a rectangle has a length that is 4 times longer than it's width. If the total area of the rectangle is 121 square feet, what is
larisa86 [58]

Answer:

L = 22 ft

Step-by-step explanation:

Let L and W represent the length and width respectively.

L = 4W, or W = L/4.  Use W = L/4 because we want to solve for W, not for L.

Area of a rectangle:  A = L · W

Here,                          A =  L · L/4 = 121 ft²

Mult. both terms by 4 removes the fraction:

                                         L² = 484

Finding the square root of this result:  L = 22

The length of the rect. is 22 ft.

5 0
3 years ago
Read 2 more answers
Observe that equation (3) has constant coefficients. If y1(x) and y2(x) form a fun- damental set of solutions of equation (3), s
WARRIOR [948]

The equations (2) and (3) you referred to are unavailable, but it is clear that you are trying to show that two set of solutions y1 and y2, to a (second-order) differential equation are solutions, and form a fundamental set. This will be explained.

Answer:

SOLUTION OF A DIFFERENTIAL EQUATION.

Two functions y1 and y2 are set to be solutions to a differential equation if they both satisfy the said differential equation.

Suppose we have a differential equation

y'' + py' + qy = r

If y1 satisfies this differential equation, then

y1'' + py1' + qy1 = r

FUNDAMENTAL SET OF DIFFERENTIAL EQUATION.

Two functions y1 and y2 are said to form a fundamental set of solutions to a second-order differential equation if they are linearly independent. The functions are linearly independent if their Wronskian is different from zero.

If W(y1, y2) ≠ 0

Then solutions y1 and y2 form a fundamental set of the given differential equation.

7 0
3 years ago
You are selling tickets to a local concert. So far you have sold a total of 350 advance tickets for students and adults. The tot
pashok25 [27]

Answer:65each have you sold?

Step-by-step explanation:

8 0
3 years ago
Any of these will help???? Please help me
alexandr402 [8]
1= 70
2= 320
3= 50

I can't do the others I'm sorry but I hope that I helped
6 0
3 years ago
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