Answer:
last set of numbers will be<em><u> 1 9 2 0</u></em>
1)
I:y=3x-4
II:9x-3y=14
substitute y into II:
9x-3*(3x-4)=14
9x-9x+12=14
12=14
this is obviously not equal so there is no solution, the lines are parallel
2)
I:y=4x+6
II:5x-y=6
substitute y into II:
5x-(4x+6)=6
5x-4x-6=6
x=12
substiute x into II:
5*12-y=6
-y=6-60
-y=-54
y=54
the solution is (12,54)
hey, I'm not sure about this answer, but I think it's true, sorry
m(2g+5mk)
Answer:
16, 104, 1000
Step-by-step explanation:
8*2
8*13
8*125