16% percent of the students paid MORE than Jane.
The mean(μ) of money spent on textbooks is 500
The standard deviation(σ) of money spent on textbooks is 50
Money paid by Jane for her books is $550
We will use this formula,
Ζ=x-μ/σ
To find: the percentage of students paid MORE than Jane for the textbooks
=?
Solution:
≤
=
Ζ≤
=1-P(Ζ≤ 1)
=1-0.8413
=0.1587
≈16%
Therefore, 16% percent (approx) of the students paid MORE than Jane.
Learn more about mean and standard deviation here brainly.com/question/4388715
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Pi is approximately 3.14.
Or if you want precision, here's the first 1000 places...
<span>3.14159265358979323846264338327950288419716939937510
58209749445923078164062862089986280348253421170679
82148086513282306647093844609550582231725359408128
48111745028410270193852110555964462294895493038196
44288109756659334461284756482337867831652712019091
45648566923460348610454326648213393607260249141273
72458700660631558817488152092096282925409171536436
78925903600113305305488204665213841469519415116094
33057270365759591953092186117381932611793105118548
07446237996274956735188575272489122793818301194912
98336733624406566430860213949463952247371907021798
60943702770539217176293176752384674818467669405132
00056812714526356082778577134275778960917363717872
14684409012249534301465495853710507922796892589235
42019956112129021960864034418159813629774771309960
51870721134999999837297804995105973173281609631859
50244594553469083026425223082533446850352619311881
71010003137838752886587533208381420617177669147303
59825349042875546873115956286388235378759375195778
18577805321712268066130019278766111959092164201989</span>
Hmm, this answer is mathematically incorrect. If the question has no errors, 38 can go into 7 0 times, it can't because its bigger than 7.
However, if it were meant to be the other way round, how many times does 7 go into 38, the answer would be 5.
You basically just split it right down the middle. if the cost of something is lets say $75.58, then you would divide 75.58 by 2, which is $37.79
hope it helps!!
Use the difference of squares factorization - that for any numbers a and b, (a-b)(a+b)=a^2-b^2.
We have:
(x^2+1)(x^2-1)=x^4-1
In addition:
(x-1)(x+1)=x^2-1, so we have:
(x^2+1)(x+1)(x-1)
As our complete factorization.
