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Natali [406]
3 years ago
8

Sin^2 x + 3sin x + 2 = 0f for 0 <= x <= 2pi Solve for x Worth 8 marks.

Mathematics
1 answer:
makvit [3.9K]3 years ago
5 0

Step-by-step explanation:

first inequality gives

(2sinx−1)(sinx+2)>0

(sinx−

2

1

)>0

6

Π

<x<

6

5Π

second inequality gives

(x+1)(x−2)<0

−1<x<2

common part is

6

Π

<x<2

hOpe it help!!!

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The two figures are congruent. Find the values of the unknown variables.
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Answer:

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Step-by-step explanation:

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4 years ago
I️ need to find the answer
kolbaska11 [484]
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3 years ago
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vfiekz [6]

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I hope this helps:

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