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Gre4nikov [31]
3 years ago
10

Help please . Thank you

Mathematics
1 answer:
MArishka [77]3 years ago
7 0
The general form is ax²+bx+c=0,
so at least we know b has to be 0. None of the values match unless we multiply everything by 4. That leads to answer B, a=1, b=0 and c=20
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Read 2 more answers
-/2 points
Rom4ik [11]

Answer:

Part 1) The domain of the quadratic function is the interval  (-∞,∞)

Part 2) The range is the interval  (-∞,1]

Step-by-step explanation:

we have

f(x)=-x^2+14x-48

This is a quadratic equation (vertical parabola) open downward (the leading coefficient is negative)

step 1

Find the domain

The domain of a function is the set of all possible values of x

The domain of the quadratic function is the interval

(-∞,∞)

All real numbers

step 2

Find the range

The range of a function is the complete set of all possible resulting values of y, after we have substituted the domain.

we have a vertical parabola open downward

The vertex is a maximum

Let

(h,k) the vertex of the parabola

so

The range is the interval

(-∞,k]

Find the vertex

f(x)=-x^2+14x-48

Factor -1 the leading coefficient

f(x)=-(x^2-14x)-48

Complete the square

f(x)=-(x^2-14x+49)-48+49

f(x)=-(x^2-14x+49)+1

Rewrite as perfect squares

f(x)=-(x-7)^2+1

The vertex is the point (7,1)

therefore

The range is the interval

(-∞,1]

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