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saw5 [17]
3 years ago
9

If 5:x=9:3 then 9x=?

Mathematics
1 answer:
devlian [24]3 years ago
3 0

Answer:

9x=15, and x= 1.6 infinite

Step-by-step explanation:

5:x=9:3 is basically 5/x=9/3 if there is 9x, it is equal to 5*3, or 15.

It is 9x because they did cross multiplication

So do it to the other side

and the answer is 9x=15

<Hope it helped!> ~❤️

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Subtract 7x-9 from2x^2-11
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Answer:

The answer is: 2x^2-7x-2

Step-by-step explanation:

we are asked to subtract 7x-9 from 2x^2-11

so, 2x^2-11-(7x-9)\\=2x^2-11-7x+9\\=2x^2-7x-2.

Hence the desired result is:  2x^2-7x-2.


8 0
3 years ago
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A section of concrete pipe 30m long has an inside diameter of 1.2m and an outside diameter of 1.8m. what is the volume of concre
Fudgin [204]

length of pipe= 30m

Inside dia. = 1.2m

Outside dia. = 1.8m


Volume of concrete= (outside dia. - inside dia.)h

V= (pi)
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v= (3.3534-1.1304)30
v=(2.233)30 = 66.690m cube

since it's volume the answer 66.690 is in cubic meters.

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3 years ago
Plz need help on a quiz???
Likurg_2 [28]
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Write 7/14 • (-7/12) in lowest terms
Marizza181 [45]
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Calculate the area of the triangle with the following vertices (3, -7), (6, 4), (-2, -3)
Monica [59]

Answer:

\boxed{\mathsf{A} \triangle = \red{\dfrac{67}{2}u.a}}

Step-by-step explanation:

Let's follow up with the solution. Considering a triangle with the vertices \mathsf{A(x_A, y_A)}, \mathsf{B(x_B, y_B)} and \mathsf{C(x_C, y_C)}, have a look at the representation in the cartesian plan.

From this representation we can say that the area (A) of a triangle through the knowledge of <u>analytical geometry</u> is given by the determinant of the vertices divided by two, mathematically,

\mathsf{A} \triangle =  \dfrac{\left| \begin{array}{ccc}  \mathsf{x_A} & \mathsf{y_A }& 1 \\  \mathsf{x_B} &  \mathsf{ y_B} & 1 \\ \mathsf{ x_C} &  \mathsf{ y_C} & 1 \end{array} \right|}{2}

So, applying this knowledge we're going to have,

\mathsf{A} \triangle =  \dfrac{\left| \begin{array}{ccc}  3 & -7 & 1 \\ 6 &  4 & 1 \\ -2 &  -3 & 1 \end{array} \right|}{2}

\mathsf{A} \triangle =  \dfrac{1}{2}\left[  \left.\begin{array}{ccc}   3 & -7 & 1 \\ 6 &  4 & 1 \\ -2&  -3 & 1 \end{array}  \right| \begin{array}{cc} 3 & -7 \\ 6 & 4 \\ -2 & -3 \end{array} \right]

\mathsf{A} \triangle = \dfrac{12 + 14 - 18 - (-8 - 9 - 42)}{2}

\red{\mathsf{A} \triangle = \dfrac{67}{2} = 33,5u.a}

Hope you enjoy it, see ya!)

\green{\mathsf{FROM}}: Mozambique, Maputo – Matola City – T-3

DavidJunior17

3 0
3 years ago
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