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svp [43]
2 years ago
9

14. Twelve more than seven times a number equals the number less six

Mathematics
2 answers:
kotegsom [21]2 years ago
3 0

Answer:

The number is -3.

Step-by-step explanation:

Set up an equation:

Variable n = number

12 + 7n = n - 6

Assuming the question is solve for n, isolate the variable:

Subtract n from both sides:

12 + 6n = -6

Subtract 12 from both sides:

6n = -18

Divide by 6 on both sides:

n = -3

Check your work:

12 + 7(-3) = -3 - 6

12 - 21 = -3 - 6

-9 = -9

Correct

Zina [86]2 years ago
3 0
12+7n=n-6
12+6n=-6
6n=-18
n=-3
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Step-by-step explanation:

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3 years ago
Expand<br> (2x - 3)4 <br><br> Can you help me expand this by using the binomial theorem?
saw5 [17]

The value of expanding (2x -3)^4 is 16x^4  + 96x^3  +216x^2 -216x + 81

<h3>How to expand the expression?</h3>

The expression is given as:

(2x -3)^4

Using the binomial expansion, we have:

(2x -3)^4 = ^4C_0 * (2x)^4 * (-3)^0 +^4C_1 * (2x)^3 * (-3)^1 + ^4C_2 * (2x)^2 * (-3)^2 + ^4C_3 * (2x)^1 * (-3)^3 + ^4C_4 * (2x)^0 * (-3)^4

Evaluate the combination factors.

So, we have:

(2x -3)^4 = 1 * (2x)^4 * (-3)^0 + 4 * (2x)^3 * (-3)^1 + 6 * (2x)^2 * (-3)^2 + 4 * (2x)^1 * (-3)^3 + 1 * (2x)^0 * (-3)^4

Evaluate the exponents and the products

(2x -3)^4 = 16x^4  + 96x^3  +216x^2 -216x + 81

Hence, the value of expanding (2x -3)^4 is 16x^4  + 96x^3  +216x^2 -216x + 81

Read more about binomial expansions at:

brainly.com/question/13602562

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Easiest way is if you substitute each point (x,y) into each set of equations and both points work for both equations in the system of equations, then it is the correct answer

Otherwise substitute one equation for y in the other equation:
2x + 6 = x^2 + 5x + 6
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0 = x^2 + 3x. Factor
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(0 , 6) And. (-3 , 0)

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3 years ago
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