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Arte-miy333 [17]
3 years ago
11

Can you draw a triangle with vertices (1,5) (5,8 ) (13,14) give reason​

Mathematics
1 answer:
Firdavs [7]3 years ago
8 0

Answer:

Step-by-step explanation:

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What are all natural numbers using the digits 7 , 0 ,6 without repeating the numbers​
Lelu [443]

Answer:

Step-by-step explanation:

The natural numbers can be :

076

067

706

760

607

and 670

Hope this helps

plz mark as brainliest!!!!!!

7 0
3 years ago
Which point is collinear with points a and d
Art [367]
B. (6, -8)

First, you need to figure out the slope of the line

(y1 - y2) / (x1 - x2)

After substituting points D(-3, 4) A(3, -4)

[4 - (-4)] / (-3 - 3)
(8) / (-6)

The slope of the line is -8/6 or -4/3 simplified

Then you can put it in point slope form:

(y - y1) = m(x - x1)

(y - y1) = -4/3(x - x1)

The point that I am using for point slope form is A(3, -4)

[y - (-4)] = -4/3(x - 3)
y + 4 = -4/3(x - 3)

Next you have to simplify the equation so that y is isolated

y + 4 = -4/3(x - 3)

First distribute the -4/3

y + 4 = -4/3(x) + (-4/3)(-3)
y + 4 = -4/3x + 4

Subtract 4 on both sides
y + 4 - 4 = -4/3x + 4 - 4
y = -4/3x

Now that you have y = -4/3x, you can substitute the values until one of them makes the equation equal

For example) (6, -8)
-8 = -4/3(6)
-8 = -8

So since (6, -8) fits in the slope intercept equation, it must me collinear with points A and D

~~hope this helps~~

6 0
3 years ago
Explain plssssssssssssssss
irina [24]
So the problem is asking you to combine equations, in this case the Y factor will cancel out so you will be left with the X factor and the total after you add both of the totals together,
6x-4y=16
5x+4y=6
6x-5x=x
16+6=22
x=22
7 0
2 years ago
If you made $300 one week and had a total of $75 worth of deductions, how much did you actually take home?
UNO [17]

Answer:

$225

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Can someone help me with this problem asap
xenn [34]

Answer:

f(x) = $ x^4 - 2x^3 + 49x^2 - 18x + 360 $ is the required polynomial.

Step-by-step explanation:

Given the zeroes (roots) of the polynomial are $ -3i $ and $ 2 + 6i $.

We know that complex roots occur in conjugate pairs.

So, this means that $ +3i $ and $ 2 - 6i $ would also be the roots of the polynomial.

If $ \pm 3i $ are to be the roots of the polynomial then the polynomial should have been: $ x^2 + 9 = 0$.

Now, to determine the polynomial for which $ 2 \pm 6i $ would be the roots.

Roots of the polynomial are nothing but the values of x (any variable) that would make the polynomial zero.

⇒ $ x = 2 + 6i \hspace{35mm} x = 2 - 6i $

⇒ $ x - 2 - 6i = 0 \hspace{25mm} x - 2 + 6i = 0 $

The required polynomial would be the product of all the above polynomials.

$ i.e., (x^2 + 9)(x - 2 + 6i)(x - 2 - 6i) = 0 $

Multiply this to get the required equation.

⇒$ (x^2 + 9)(x^2 - 2x + 40) $

$ \implies x^4 - 2x^3 + 40x^2 + 9x^2 - 18x + 360 = 0 $

∴ The required polynomial is x⁴ - 2x³ + 49x² - 18x + 360 = 0.

3 0
3 years ago
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