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BlackZzzverrR [31]

3 years ago

7

a kennel is moving 160 dogs each have their own cage they rent 17 trucks 9 dogs are already in creates write a division problem

to find the number of trucks needed to cary the dogs

1 answer:

olchik [2.2K]3 years ago

4 0

160 divided by 9 = the amount of trucks needed. (17.7 therefore you would need to rent 18 trucks)

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Bob traveled 90 miles which was 83 1/3 % of his trip. How long was the trip?

lilavasa [31]

Let x be total amount traveled Therefore, x(.8333) = 90 x = 108 108 miles

hope i helped

5 0

3 years ago

Read 2 more answers

What is the value of p?

user100 [1]

Answer:

A

Step-by-step explanation:

The angle adjacent to 133 and 133 form a straight angle and are supplementary, hence

adjacent angle = 180° - 133° = 47°

The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles. The angle 90 is an exterior angle, thus

p + 47 = 90 ( subtract 47 from both sides )

p = 43° → A

3 0

4 years ago

Whats the density of an object with the length of 5.0 cm a height of 3.0 and width of 15.0 cm and a mass of 24 grams

Sphinxa [80]

Answer:

The density of the object is $0.1067$ grams per cubic centimeter. (Rounded off to 4th decimal)

Step-by-step explanation:

Density = [Mass/Volume]

Here we have been given the dimensions of the object.

Volume = Height * Width * Length

Volume = $3.0cm*15.0cm*5.0cm$

= $225cm^{3}$

Now we can substitute the Mass and the Volume to the density equation.

Density = [Mass/Volume]

= $\frac{24grams}{225cm^{3} }$

= $0.1067$ grams per cubic centimeter. (Rounded off to 4th decimal)

4 0

3 years ago

11X - 3/6 = 5 Solve for X

german

Answer:

X = 1/2

Step-by-step explanation:

5 0

3 years ago

Express the product of z1 and z2 in standard form given that <img src="https://tex.z-dn.net/?f=z_%7B1%7D%20%3D%20-3%5Bcos%28%5Cf

Marta_Voda [28]

Answer:

Solution : 6 + 6i

Step-by-step explanation:

$-3\left[\cos \left(\frac{-\pi }{4})\right+i\sin \left(\frac{-\pi }{4}\right)\right]\cdot \:2\sqrt{2}\left[\cos \left(\frac{-\pi }{2}\right)+i\sin \left(\frac{-\pi }{2}\right)\right]$

This is the expression we have to solve for. Now normally we could directly apply trivial identities and convert this into standard complex form, but as the expression is too large, it would be easier to convert into trigonometric form first ----- ( 1 )

( Multiply both expressions )

$-6\sqrt{2}\left[\cos \left(\frac{-\pi }{4}+\frac{-\pi \:\:\:}{2}\right)+i\sin \left(\frac{-\pi \:}{4}+\frac{-\pi \:\:}{2}\right)\right]$

( Simplify $\left(\frac{-\pi }{4}+\frac{-\pi }{2}\right)$ for both $\cos \left(\frac{-\pi }{4}+\frac{-\pi }{2}\right)$ and $i\sin \left(\frac{-\pi }{4}+\frac{-\pi }{2}\right)$ )

$\left(\frac{-\pi }{4}+\frac{-\pi }{2}\right)$ = $\left(-\frac{3\pi }{4}\right)$

( Substitute )

$-6\sqrt{2}\left(\cos \left(-\frac{3\pi }{4}\right)+i\sin \left(-\frac{3\pi }{4}\right)\right)$

Now that we have this in trigonometric form, let's convert into standard form by applying the following identities ----- ( 2 )

sin(π / 4) = √2 / 2 = cos(π / 4)

( Substitute )

$-6\sqrt{2}\left(-\sqrt{2} / 2 -i\sqrt{2} / 2 )$

= $-6\sqrt{2}\left(-\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}i\right)$ = $-\frac{\left(-\sqrt{2}-\sqrt{2}i\right)\cdot \:6\sqrt{2}}{2}$

= $-3\sqrt{2}\left(-\sqrt{2}-\sqrt{2}i\right)$ = $-3\sqrt{2}\left(-\sqrt{2}\right)-\left(-3\sqrt{2}\right)\sqrt{2}i$

= $3\sqrt{2}\sqrt{2}+3\sqrt{2}\sqrt{2}i:\quad 6+6i$ - Therefore our solution is option a.

4 0

4 years ago