Hi there!
Since ST is a tangent to the circle, we can use the relationship: tangent squared = external secant segment x entire secant segment.
WORK:
(I will be using x in place of ST)
x^2 = 7(23 + 7)
x^2 = 7(30)
x^2 = 210
x = squareroot(210) or approximately 14.5 inches
Hope this helps!! :)
Answer:
0.5625 ft^2
Step-by-step explanation:
area of square = side * side
A = s^2
A = (0.75 ft)^2 = (0.75 ft)(0.75 ft) = 0.5625 ft^2
Answer:
(-2,-12), (-1,-6), (0,-3) and (1,-3/2)
Step-by-step explanation:
g(x) = -3(1/2)^x
Putting values of x
x g(x)
-2 -3(1/2)^-2 = -12
-1 -3(1/2)^-1 = -6
0 -3(1/2)^0 = -3
1 -3(1/2)^1 = -3/2
Now, making the graph we will plot
(-2,-12), (-1,-6), (0,-3) and (1,-3/2)
The graph is shown in figure below.
Answer:
Its (10,∞)
Step-by-step explanation:
Trust me I just took the exam and got it correct
Sec is 1/cos so sec -120 is 1/cos -120 which is -2