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adelina 88 [10]
3 years ago
6

I NEED HELP ASAP PLEASEEEE​

Mathematics
1 answer:
spin [16.1K]3 years ago
5 0

Answer:

Step-by-step explanation:

1) Find the Mean of all the numbers.

3+4+5+7+10+12+15=56

56/7=8 mean is 8

Now We Calculate Standard Deviation:

S=\sqrt{(3-8)^2+(4-8)^2+(5-8)^2+(7-8)^2+(10-8)^2+(12-8)^2+(15-8)^2}

You take each number from the problem i.e 3,4,5...

and then you subtract the mean from it and then square it.

S=\sqrt{(-5)^2+(-4)^2+(-3)^2+(-1)^2+(2)^2+(4)^2+(7)^2}

S=\sqrt{25+16+9+1+4+16+49}

S=\sqrt{120}

S=\sqrt{120}/7

7 is the amount of data units given in the problem.

120/7=17.1428571429

\sqrt{17.1428571429} =4.1403933560541

Nearest hundredth=4.14

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stich3 [128]
HELPP w my shiiiii plzzzzz
4 0
4 years ago
Please answer this question!!<br><br>thanks xx
Simora [160]
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Hope this helps :)
7 0
4 years ago
Can some one help i need to pass
Goryan [66]
It is easy, just add up the numbers and divide by how many set of numbers there is.
6 0
2 years ago
A family of 4 spent $104 for tickets to a concert on Friday and they spent $140 for tickets to a dinner theater on Saturday. All
Julli [10]

Answer:

  • Friday's tickets: $26 each
  • Saturday's tickets: $35 each

Step-by-step explanation:

We presume that 4 tickets were bought each day, so the price of 1 ticket is 1/4 of the total price:

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  (1/4)($140) = $35

The cost of each ticket on Friday was $26; on Saturday, the cost was $35.

5 0
3 years ago
Help me please I'm stuck! With the first column
frosja888 [35]
1. \frac{n}{4}

2. -2+5n or 5n-2

3. (12s)+150 where s=number of students

4. 3(32)+1(53)=96+53=159 per hour, so 159h

9. √105 is irrational, -4 is an integer, 4/3 is a rational number, order is -4,3/4, √105

10. 3²=9, 4²=16, so between 3 and 4, but closer to 4, so √14≈4

11. that is the associative property, it deals with moving parentahees around

12. 2(6.25)+1(5.50)+2(2.75)=2(6.25+2.75)+1(5.50)=2(9)+5.5=18+5.5=23.5

13. yes, because they are both 2 less than 3 times of a number

14. maybe 18 times 3, so (4²+2) times 3=54
5 0
4 years ago
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