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azamat
3 years ago
5

Please answer this question!!thanks xx

Mathematics
1 answer:
Simora [160]3 years ago
7 0
180-(180-49-48)
180-(83)
97

180-((180-141)+(180-76))
180-(39+104)
180-143
137

180-((180-101)+60)
180-(79+60)
180-139
41

360-147-79
213-79
139

180-(360-109*2)
180-(360-218)
180-142
38

(180-118)/2
62/2
31

Hope this helps :)
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Suppose that each time Giannis Antetokounmpo shoots a free throw, he has a 3/4 probability of success. If Giannis shoots three f
GREYUIT [131]

Answer:

84.38% probability that he succeeds on at least two of them

Step-by-step explanation:

For each free throw, there are only two possible outcomes. Either Giannis makes it, or he does not. The free throws are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

He has a 3/4 probability of success.

This means that p = \frac{3}{4} = 0.75

Giannis shoots three free throws

This means that n = 3

What is the probability that he succeeds on at least two of them

P(X \geq 2) = P(X = 2) + P(X = 3)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{3,2}.(0.75)^{2}.(0.25)^{1} = 0.4219

P(X = 3) = C_{3,3}.(0.75)^{3}.(0.25)^{0} = 0.4219

P(X \geq 2) = P(X = 2) + P(X = 3) = 0.4219 + 0.4219 = 0.8438

84.38% probability that he succeeds on at least two of them

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Which two integers is square root -21 between?
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None

Step-by-step explanation:

None. √-21 is not a real number.

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There are 4 quarts in 1 gallon.

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I hope this helps :)

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If y = -x² + 14x + 7 , then x = 10 is a counterexample for which conjecture?
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Answer:

The correct answer is B

Step-by-step explanation:

If we plug in x=10 to the equation, we get y=47

Since y is positive, A is not an counterexample

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