The cost of parking is an initial cost plus an hourly cost.
The first hour costs $7.
You need a function for the cost of more than 1 hour,
meaning 2, 3, 4, etc. hours.
Each hour after the first hour costs $5.
1 hour: $7
2 hours: $7 + $5 = 7 + 5 * 1 = 12
3 hours: $7 + $5 + $5 = 7 + 5 * 2 = 17
4 hours: $7 + $5 + $5 + $5 = 7 + 5 * 3 = 22
Notice the pattern above in the middle column.
The number of $5 charges you add is one less than the number of hours.
For 2 hours, you only add one $5 charge.
For 3 hours, you add two $5 charges.
Since the number of hours is x, according to the problem, 1 hour less than the number of hours is x - 1.
The fixed charge is the $7 for the first hour.
Each additional hour is $5, so you multiply 1 less than the number of hours,
x - 1, by 5 and add to 7.
C(x) = 7 + 5(x - 1)
This can be left as it is, or it can be simplified as
C(x) = 7 + 5x - 5
C(x) = 5x + 2
Answer: C(x) = 5x + 2
Check:
For 2 hours: C(2) = 5(2) + 2 = 10 + 2 = 12
For 3 hours: C(3) = 5(3) + 2 = 15 + 2 = 17
For 4 hours: C(3) = 5(4) + 2 = 20 + 2 = 22
Notice that the totals for 2, 3, 4 hours here
are the same as the right column in the table above.
Hey there!
ANSWER: 
EXPLANATION:
To find the answer to your question, you will need to add.
First, multiply the denominator.
So the denominator will be 20.
Now move on to the numerator. Multiply 5 by 3.
Now multiply 4 bu 2.
If you want to get the numerator, add what you got after multiply.
The numerator is 23. So now let's complete the fraction.
This is your answer!
Hope this helps!
Answer:
A = 1500
3 years = $18,644.48
30 years = $132,032.78
Step-by-step explanation:
Q is located at (-5,2)
Q" is located at (6,2)
they bot h have the same Y value (2) so we know it was only a reflection across the X axis
we need to find out where on the X axis it was reflected.
the distance between -5 and 6 = 11 units
11/2 = 5.5
the reflection line was 5.5 units to the right of the original Q
so the reflection line would be X = 0.5
