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Yuri [45]
3 years ago
9

Answer it fast please​

Mathematics
1 answer:
fgiga [73]3 years ago
3 0
(3/5)^3 x (3/5)^-2
= (3/5)^1
= 3/5
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Maximizing revenue. Edwards University wants to determine what price to charge for tickets to football games. At $18 per ticket,
Papessa [141]

Answer:

New price is $12.75

New attendance is 57500

Step-by-step explanation:

For starters, we use the relation.

18 - 3x

Since we don't know the number of times we're expected to deduct $3 from the price.

Again, we have 40000 + 10000x on another hand. Question says to add 10000 people everytime $3 is deducted.

Since (40000 + 10000x) is the number of people, we multiply it by $4.50, the average amount each person spends is then gotten to be

(18 - 3x) (40000 + 10000x) + (40000 + 10000x) (4.5) = 0

Expanding the bracket, we have

[720000 + 60000x - 30000x²] + [180000 + 45000x] = 0, solving further, we have

900000 + 105000x - 30000x² = 0 or

-30000x² + 105000x + 900000 = 0

Then, we find the maximum of a quadratic, by finding the axis of symmetry. Use x = -b/2a

x = -105000 / 2 * -30000

x = -105000 / -60000

x = 1.75

From our earlier equations, the new price then is

18 - 3(1.75) = 18 - 5.25 = $12.75

The new attendance also is

40000 + 10000(1.75) =

40000 + 17500 = 57500

7 0
3 years ago
Two angles of a quadrilateral are 40 degree and 60 degree and the ratio of remaining two angles is 7:6. The degree measure of re
Semenov [28]

Answer:

140,120

Step-by-step explanation:

sum of angles in a quadrilateral =360

sum of the 1st two angles=60+40=100

360-100=260

the ratio of the remaining angles 7:6

therefore:

\frac{7}{13}  \times 260

=140

for the second angle

260-140=120

5 0
2 years ago
Engineers must consider the breadths of male heads when designing helmets. The company researchers have determined that the popu
tia_tia [17]

Answer:

The minimum head breadth that will fit the clientele is 4.4 inches.

The maximum head breadth that will fit the clientele is 7.8 inches.

Step-by-step explanation:

Let <em>X</em> = head breadths of men that is considered for the helmets.

The random variable <em>X</em> is normally distributed with mean, <em>μ</em> = 6.1 and standard deviation, <em>σ</em> = 1.

To compute the probability of a normal distribution we first need to convert the raw scores to <em>z</em>-scores using the formula:

z=\frac{x-\mu}{\sigma}

It is provided that the helmets will be designed to fit all men except those with head breadths that are in the smallest 4.3% or largest 4.3%.

Compute the minimum head breadth that will fit the clientele as follows:

P (X < x) = 0.043

⇒ P (Z < z) = 0.043

The value of <em>z</em> for this probability is:

<em>z</em> = -1.717

*Use a <em>z</em>-table.

Compute the value of <em>x</em> as follows:

z=\frac{x-\mu}{\sigma}\\-1.717=\frac{x-6.1}{1}\\x=6.1-(1.717\times 1)\\x=4.383\\x\approx4.4

Thus, the minimum head breadth that will fit the clientele is 4.4 inches.

Compute the maximum head breadth that will fit the clientele as follows:

P (X > x) = 0.043

⇒ P (Z > z) = 0.043

⇒ P (Z < z) = 1 - 0.043

⇒ P (Z < z) = 0.957

The value of <em>z</em> for this probability is:

<em>z</em> = 1.717

*Use a <em>z</em>-table.

Compute the value of <em>x</em> as follows:

z=\frac{x-\mu}{\sigma}\\1.717=\frac{x-6.1}{1}\\x=6.1+(1.717\times 1)\\x=7.817\\x\approx7.8

Thus, the maximum head breadth that will fit the clientele is 7.8 inches.

5 0
3 years ago
I need help do y’all know answer…..
Tems11 [23]

Answer:

x = 70

Step-by-step explanation:

14 + x = 84

x= 84 - 14

x = 70

here x is the games lost.

hope tgis helps !

4 0
2 years ago
Calcule:
zaharov [31]
<span>a. 8                                                                                                                                    b. 20                                       </span><span>                                                                                            c. 4                                                                                                                                     d. 16/5                                                                                                                                 e. 10                                                                                                                                   f.   5                                                                                                                                     g.  2                                                                                                                                     h.  8/3</span>
3 0
3 years ago
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