Ill give brainliest.

Quadrilateral PUMA has coordinates at P(-5,-2), U(-1,2), M(4,-3), A(0,-7) and it is transformed by (x+3,y-5). Determined the ima

IgorLugansk [536]

The image of M is (7 , -8)

Step-by-step explanation:

Let us revise some transformation

If the point (x , y) translated horizontally to the right by h units then its image is (x + h , y)
If the point (x , y) translated horizontally to the left by h units then its image is (x - h , y)
If the point (x , y) translated vertically up by k units then its image is (x , y + k)
If the point (x , y) translated vertically down by k units then its image is (x , y - k)

∵ The quadrilateral PUMA has coordinates at:

P (-5 , -2) , U (-1 , 2) , M (4 , -3) , A (0 , -7)

∵ It is transformed by (x + 3 , y - 5)

- That means the quadrilateral translated 3 units right and 5 units

down, then we add each x-coordinate by 3 and subtract 5 from

each y-coordinate

∵ The coordinates of point M are (4 , -3)

∴ The image of point M = (4 + 3 , -3 - 5)

∴ The image of point M = (7 , -8)

The image of M is (7 , -8)

Learn more:

You can learn more about transformation in brainly.com/question/5563823

brainly.com/question/11203617

*LearnwithBrainly

8 0

3 years ago

Find a new function g(x) transformed from f(x)=-x-2 such that g(x) is perpendicular to f(x) .

sineoko [7]

The new function is g(x) =-1(1/-x) +2.

The transformation of function f(x) to function g(x) is given by g(x)=A f(Bx+ H)+K. where the constant A scales the function vertically. (A negative A reflects the function about the x-axis B scales the function horizontally. (A negative B reflects the function on the y-axis.) H shifts the function horizontally, and K shifts the function vertically.

Convert f(x) to g(x)

where the conversion is g(x)=f(x)+2.

A perpendicular line has negative reciprocal slopes, so for g(x) to be perpendicular to f(x), we need to get the negative reciprocal of -x, which is -1(1/-x)

So, f(x)=-x-2 ; m = -1

From the above information, we get g(x) as follows.

g(x) =-1(1/-x) +2

More problems related to finding new functions for a given function are below.

brainly.com/question/13825802?referrer=searchResults

#SPJ4

6 0

1 year ago

Rationalize the denominator of $\frac{5}{2+\sqrt{6}}$. The answer can be written as $\frac{A\sqrt{B}+C}{D}$, where $A$, $B$, $C$

horrorfan [7]

Answer:

$A +B+C+D = 3$ is the correct answer.

Step-by-step explanation:

Given:

$\frac{5}{2+\sqrt{6}}$

To find:

$A+B+C+D = ?$ if given term is written as following:

$\frac{A\sqrt{B}+C}{D}$

<u>Solution:</u>

We can see that the resulting expression does not contain anything under $\sqrt$ (square root) so we need to rationalize the denominator to remove the square root from denominator.

The rule to rationalize is:

Any term having square root term in the denominator, multiply and divide with the expression by changing the sign of square root term of the denominator.

Applying this rule to rationalize the given expression:

$\dfrac{5}{2+\sqrt{6}} \times \dfrac{2-\sqrt6}{2-\sqrt6}\\\Rightarrow \dfrac{5 \times (2-\sqrt6)}{(2+\sqrt{6}) \times (2-\sqrt6)} \\\Rightarrow \dfrac{10-5\sqrt6}{2^2-(\sqrt6)^2}\ \ \ \ \ (\because \bold{(a+b)(a-b)=a^2-b^2})\\\Rightarrow \dfrac{10-5\sqrt6}{4-6}\\\Rightarrow \dfrac{10-5\sqrt6}{-2}\\\Rightarrow \dfrac{-5\sqrt6+10}{-2}\\\Rightarrow \dfrac{5\sqrt6-10}{2}$