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3 years ago

Write an integer that represents a withdrawl of $44.00 from your bank account

Mathematics

1 answer:

natulia [17]3 years ago

7 0

Answer:

-44

Step-by-step explanation:

Because a withdrawal is removing money, it will be negative. The value is 44, so the integer is -44.

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PQ is a diameter of a circle with centre If angle PQR=55 ,SPR=25 and angle PQM=50

tigry1 [53]

Answer:

m∠QPR = 35° m∠QPM =40° m∠PRS = 30°

Step-by-step explanation:

ΔPRQ is a right triangle with right angle at R. So m∠QPR = 90 - 55 = 35

ΔQPM is a right triangle with right angle at M. So m∠QPM = 90 - 40 = 40

Arc RQ = 2(35) = 70 and arc SR = 2(25) = 50.

So arc PS = 180 - (arc RQ + arc SR) = 180 - (70 + 50) = 180 - 120 = 60

Now arc PS is the intercepted arc for ∠PRS.

Therefore, m∠PRS = 60/2 = 30

I used the fact that an inscribed angle has a measure 1/2 the measure of the intercepted arc several times. Also, I used the fact that the acute angles of a right triangle are complementary. And, finally I used the fact that an inscribed angle in a semicircle is a right angle.

I hope this helped.

5 0

3 years ago

Someone please help me understand

dimulka [17.4K]

Step-by-step explanation:

u have to say what the how much degree it is

3 0

3 years ago

Find angle ADB of the equation

Aloiza [94]

Answer:

$m\angle ADB = 59\°$ .

Step-by-step explanation:

Given:

$\angle BDC = 31\°$

We need to find $\angle ADB$ .

Solution:

Now we can see that given figure is a rectangle with diagonals drawn in it.

So by properties of rectangle which states that;

"All angles of a rectangle are 90°."

So we can say that;

$\angle A = \angle B = \angle C = \angle D = 90\°$

But

$\angle D = \angle BDC + \angle ADB$

Substituting the values we get;

$31\°+\angle ADB = 90\°$

Subtracting both side by by 31 we get;

$31\°+\angle ADB -31\°= 90\°-31\°\\\\m\angle ADB = 59\°$

Hence $m\angle ADB = 59\°$ .

8 0

4 years ago

PLEASE HELP!! TIME LIMITT

Lelechka [254]

Using proportions, it is found that the length of the drawing is of 2.583 feet.

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Scale problems are solved using proportions, by a rule of three.
The length of the front is of 155 feet.
The drawing has a scale of 1/60 of the actual size, that is, each actual feet is worth 1/60 on the drawing.

Thus:

1 feet - 1/60 feet

155 feet - x

Applying cross multiplication:

$x = 155 \times \frac{1}{60} = \frac{155}{60} = 2.583$