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Feliz [49]
3 years ago
11

A refrigerator in the shape of a rectangular prism has a depth of 28 inches, a width of 36 inches, and a height of 66 inches. Wh

at is the volume of the refrigerator?
Mathematics
1 answer:
Vadim26 [7]3 years ago
4 0

Answer:

The volume of refrigerator is <u>66528 cubic inches</u>.

Step-by-step explanation:

Given:

A refrigerator in the shape of a rectangular prism has a depth of 28 inches, a width of 36 inches, and a height of 66 inches.

Now, to get the volume of refrigerator.

As, the refrigerator in the shape of a rectangular prism.

The dimensions of refrigerator are:

Length = 28 inches.

Width = 36 inches.

Height = 66 inches.

Now, to get the volume of the refrigerator we put formula:

Volume=length\times width\times height

Volume=28\times 36\times 66

Volume=66528\ cubic\ inches.

Therefore, the volume of refrigerator is 66528 cubic inches.

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Step-by-step explanation:

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Answer:

2x + y = -5 (which is Answer 1).

Step-by-step explanation:

The possible answer choices are all versions of the standard equation of a straight line:   Ax + By + C = 0.  If A and B are both positive, as they are here, then the slope is negative and has the form m = -A/B.  Only the first answer choice passes here:  with +2x and +1y, the slope is -2.  This automatically eliminates the other possibilities.

Looking at the first answer choice, we see that A must be 2 and B must be 1

so that the slope is m = -2.    Writing out this equation:  Ax + By + C = 0.

Replace A with 2 and B with 1:  2x + y + C = 0.

Finally, replace x with -1 and y with -3:  2(-1) + (-3) + C = 0.

Solving this for C, we get   -2 - 3 + C = 0, or -5 + C = 0, or C = 5.

We end up with 2x + y = -5 (which is Answer 1).

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"Suppose an object falling in the atmosphere has mass m=15kg and the drag coefficient is γ=9kg/s. Recall that the differential e
Art [367]

Answer:

a. v(t)= -6.78e^{-16.33t} + 16.33 b. 16.33 m/s

Step-by-step explanation:

The differential equation for the motion is given by mv' = mg - γv. We re-write as mv' + γv = mg ⇒ v' + γv/m = g. ⇒ v' + kv = g. where k = γ/m.Since this is a linear first order differential equation, We find the integrating factor μ(t)=e^{\int\limits^  {}k \, dt } =e^{kt}. We now multiply both sides of the equation by the integrating factor.

μv' + μkv = μg ⇒ e^{kt}v' + ke^{kt}v = ge^{kt} ⇒ [ve^{kt}]' = ge^{kt}. Integrating, we have

∫ [ve^{kt}]' = ∫ge^{kt}

    ve^{kt} = \frac{g}{k}e^{kt} + c

    v(t)=   \frac{g}{k} + ce^{-kt}.

From our initial conditions, v(0) = 9.55 m/s, t = 0 , g = 9.8 m/s², γ = 9 kg/s , m = 15 kg. k = y/m. Substituting these values, we have

9.55 = 9.8 × 15/9 + ce^{-16.33 * 0} = 16.33 + c

       c = 9.55 -16.33 = -6.78.

So, v(t)=   16.33 - 6.78e^{-16.33t}. m/s = - 6.78e^{-16.33t} + 16.33 m/s

b. Velocity of object at time t = 0.5

At t = 0.5, v = - 6.78e^{-16.33 x 0.5} + 16.33 m/s = 16.328 m/s ≅ 16.33 m/s

6 0
3 years ago
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