9514 1404 393
Answer:
A. 0 = −(x−6)^2+12
Step-by-step explanation:
The vertex form of a quadratic equation is ...
y = a(x -h)² +k . . . . . . for vertex (h, k) and scale factor 'a'
When the given vertex (h, k) = (6, 12) is used, we find the form of the equation to be ...
y = a(x -6)² +12
The ball will be on the ground when y = 0. Here, the vertical scale factor 'a' is -1, so the equation representing the ball being on the ground is ...
0 = -(x -6)² +12 . . . . . . matches choice A
The first two are the horizontal the second one is vertical.
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Answer:
The system of this equation is ( -1, 10) which is Option A.
Step-by-step explanation:
Solve for y in the first equation.

Replace all occurrences of yy with -5x+5 in each equation.

Solve for x in the first equation.

Replace all occurrences of x with -1 in each equation.

The solution to the system is the complete set of ordered pairs that are valid solutions.
(−1, 10)
<u>Hence</u><u>,</u><u> </u><u>the</u><u> </u><u>system</u><u> </u><u>of</u><u> </u><u>this</u><u> </u><u>equation</u><u> </u><u>is</u><u> </u><u>(</u><u>-1</u><u>,</u><u> </u><u>10</u><u>)</u><u>.</u><u> </u>
<u>Option</u><u> </u><u>A</u><u>.</u>
Answer:
1/6
Step-by-step explanation: