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Solnce55 [7]
2 years ago
15

Rewrite the function by completing the square f(x)=x^2−8x−2

Mathematics
1 answer:
Oduvanchick [21]2 years ago
4 0

Answer:

x-intercept(s):(4+3\sqrt{2},0),(4-3\sqrt{2},0)

y-intercept(s): (0,-2)

Step-by-step explanation:

To find the x-intercept, substittute in 0 for y and solve for x. To find the y-intercept, substitute in 0 for x and solve for y.

Hope this helps! If not I'm very sorry.

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What is the slope of a line that has a y-intercept but no x intercept
IRINA_888 [86]

Answer:

The slope of a line that has a y-intercept but no x-intercept will be zero.

Step-by-step explanation:

If the line has no x-intercept, then it never intersects the x-axis, so it must be parallel to the x-axis.

If a line does not have an x-intercept, it means it would never intersect the x-axis.

Thus, it must be parallel to the x-axis, meaning its slope will be zero. It would be just a horizontal line.

For example, y=9 is the line equation that does not have an x-intercept and its slope is zero.

Therefore, the slope of a line that has a y-intercept but no x-intercept will be zero.

7 0
3 years ago
Plz help
riadik2000 [5.3K]
  1. 4(20+22)
  2. 4(40+2)

This expression are equivalent to 4(42)

4 0
3 years ago
HELP ME PLEASE I need answers First answer get Brainliest
Tju [1.3M]

Answer:

Step-by-step explanation:

I think it is c

4 0
3 years ago
In a triangle what is always opposite the angle with the greatest measure
Llana [10]
The longest side

Think about it. The widest angle would leave a resulting long side to reach the ends of the angle 

If you look at the picture, the side across from the widest angle has the longest length

5 0
3 years ago
Read 2 more answers
Y = 3 sin2x, y = 0, 0 ≤ x ≤ π; about the x−axis
Dominik [7]
I assume you're revolving the region with those bounds about the x-axis, and supposed to find the volume.

Via the disk method,

\displaystyle\pi\int_0^\pi(3\sin2x)^2\,\mathrm dx=9\pi\int_0^\pi\sin^22x\,\mathrm dx

Recall the half-angle identity for sine:

\sin^2t=\dfrac{1-\cos2t}2
\implies\displaystyle\frac{9\pi}2\int_0^\pi(1-\cos4x)\,\mathrm dx
=\displaystyle\frac{9\pi}2\left(x-\frac14\sin4x\right)\bigg|_{x=0}^{x=\pi}
=\dfrac{9\pi^2}2
8 0
3 years ago
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