Question

Help me find the perimeter of this figure.

Answer 1

Answer:

8+10+8+10=36+   2 x 3.14 x radium/2

Step-by-step explanation:

Answer 2

look at the semicircle

area of semicircle

${ \boxed{ \bold{ \red{A = \pi \: \times {r}^{2} }}}}$

${ \bold{ \boxed{ \red{radius = \frac{diameter}{2} } }}}$

$radius = \frac{8}{2} = \boxed{4}$

$area = 3.14 \times {4}^{2} \\ area = 50.24$

as we can see that is a parallelogram

so ,

area of parallelogram

$\boxed {\bold{ \red{area \: of \: parallelogram =b \times h }}}$

$area \: = 8 \times 10 \\ are \: = 80in$

area of fig = area of semicircle + area of parallelogram

total area = 50.24+80

total area = 130.24 in²

$\boxed{130.24 {in}^{2} }$