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Korolek [52]
3 years ago
10

A company plans to sell a new type of cleaner for $280 each. The estimated cost, y, of manufacturing the cleaners is a function

with a y-int of 11,000 and a vertex of (500, 24,000). How many must be sold for the company to make a profit?
Mathematics
1 answer:
Minchanka [31]3 years ago
4 0
Suppose x is sold, $280 each , and y is the total financial cost. The first equation in the system is then certainly y = 280x.

The vertex form  <span>y-k = a(x-h)^2 where (h,k) is the vertex, and y is the y-intercept.

So, plug the values in.
</span><span>11,000-24,000 = a(0-500)^2
-13,000=250,000a
a=-0.052

y-</span><span>24,000 = -0.052(x-500)^2
y= </span><span>-0.052(x-500)^2 + 24,000
This is the second equation in the system.

The answer is then A, which contain the system </span><span>of equations which can be used to determine must be sold for the company to make a profit.</span>
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Well, 5 tens is equivalent to 50, and 29 ones is equivalent to 29, so 50 + 29 = 79 =)
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4 years ago
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Compute the discriminant D(x,y)D(x,y) of the function. f(x,y)=x3+y4−6x−2y2+3 f(x,y)=x3+y4−6x−2y2+3 (Express numbers in exact for
Igoryamba

Answer:

Point                Critical point

Q (2,0)                 local minimum

R (-2,1)                 Saddle

S (2,-1)                  local maximum

T ( -2,-1)                Saddle

O ( -2,0)                Saddle

Step-by-step explanation: INCOMPLETE ANSWER INFORMATION ABOUT THE POINTS ARE RARE

f(x,y) = x³ +y⁴ - 6x -2y² +3

df/dx = f´(x) = 3x² -6x

df/dxdx = f´´(xx) = 6x

df/dy = f´(y) = -4y

df/dydy = 4

df/dydx = df/dxdy = 0

df/dydy = f´´(yy)

D = [ df/dxdx *df/dydy] - [df/dydx]²

D = (6x)*4 - 0

D = 6*2*4     D > 0 and the second derivative on x is  6*2 = 12

so  D > 0 and df/dxdx >0  there is a local minimum in P

Q(2,1)

D = (6*2)*4  D>0  and second derivative on x is 6*2

The same condition there is a minimum in Q

R ( -2,1)

D = 6*(-2)*4 = -48  D< 0 there is a saddle point in R

S (2,-1)

D = 6*2*4 = 48  D > 0 and  df/dxdx = 6*-1  = -6

There is a maximum in S

T ( -2,-1)

D = 6*(-2)*(4) = -48  D<0 there is a saddle point in T

O ( -2,0)

D = 6*(-2)*4 = -48 D<0  there is a saddle point in O

5 0
3 years ago
Find the height of a prism whose volume is 108 cm3<br> and the area of the base is 15 cm2.
cluponka [151]

Answer:17

Step-by-step Experlation: The volume is 108 cm. 3,2,15.a square prism with a base edge of 9.5 inches and a height of 17 ... amount for a landowner

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3 years ago
Aaron walks at a pace of 10,560 feet per half hour. How many miles does Aaron
yarga [219]
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3 years ago
Need please help with the answer
Sladkaya [172]

Step-by-step explanation:

the volume of a rotating solid out of an xy area in a certain interval is pi times the integral of that area squared (because we are emulating adding the volumes of cylinder slices) in that interval along the given axis.

if that area is defined as the difference between 2 curves, then that difference (of the squares) has to be integrated.

the "outer" curve is y = x² + 3 = R, because it has always the larger y values compared to y = 2x + 1 = r.

the volume of an outer cylinder slice is

pi × R² × dx

and of an internal cylinder slice is

pi × r² × dx

therefore, the volume of the difference "washer" cylinder is

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and now integrating the infinitely thin washers across the interval [0, 2].

R² = (x²+3)² = x⁴ +6x² + 9

r² = (2x+1)² = 4x² + 4x + 1

R² - r² = x⁴ + 2x² - 4x + 8

the integral of (R² - r²)dx :

1/5 x⁵ + 2/3 x³ - 4/2 x² + 8x = 1/5 x⁵ + 2/3 x³ - 2x² + 8x

in the interval of [0, 2] that gives us

1/5 2⁵ + 2/3 2³ - 2×2² + 8×2 - 0 = 32/5 + 16/3 - 8 + 16 =

= 32/5 + 16/3 + 8 = 96/15 + 80/15 + 120/15 = 296/15

and as final step multiplying this by pi :

296pi/15 = 61.99409503... units³ ≈ 62 units³

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