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Answer:
Step-by-step explanation:
GIVEN: A bag contain red marbles,
green marbles and
blue marble. A marble is chosen at random from the bag and not replaced, then a second marble is chose.
TO FIND: What is the probability both marbles are green.
SOLUTION:
Total marbles in bag
total number of green marbles
Probability that first marble will be green
Probability that second marble will be green
As both events are disjoint
probability both marbles are green
Hence the probability both marbles are green is
7We can see that line NM = JK so NM also equals 10.
We know NL = 23 and NM = 10 therefore, ML = NL -NM ML = 23 -13
ML = 10
The last thing to solve is the length of KL
KL = ML / sine 34
KL = 10 / 0.55919
KL = 17.9
Total fence length required = JK + KL + NL =
13 + 17.9 + 23
= 53.9 yards
Cost of Fencing = $3.50 * 53.9 =
<span> <span> <span> $188.65 </span> </span> </span>
We know NL = 23 and NM = 10 therefore, ML = NL -NM ML = 23 -13
ML = 10
The last thing to solve is the length of KL
KL = ML / sine 34
KL = 10 / 0.55919
KL = 17.9
Total fence length required = JK + KL + NL =
13 + 17.9 + 23
= 53.9 yards
Cost of Fencing = $3.50 * 53.9 =
<span> <span> <span> $188.65 </span> </span> </span>