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Katyanochek1 [597]
3 years ago
14

If f(x) = (3+x)/(x-3), what is f(a+2)​

Mathematics
1 answer:
sergey [27]3 years ago
5 0

Answer:

B

Step-by-step explanation:

To evaluate f(a + 2), substitute x = a + 2 into f(x), that is

f(a + 2) = \frac{3+a+2}{a+2-3} = \frac{5+a}{a-1}

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Nostrana [21]
3y = -2x + 2
y = x + 4 (Substitute the y)

3(x + 4) = -2x + 2 (Distribute)
3x + 12 = -2x + 2 (Add 3 to both sides)
+3x       +3x
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12 = 1x + 2 (Subtract 2 from both sides)
-2         - 2
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10 = 1x (Divide by 1 on both sides)
10/1 = 1x/1
x = 10 
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What is 4.33 as a fraction
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Answer: 4 1/3 or 13/3

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Consider the sequence 10, 2..
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Answer:  see below

<u>Step-by-step explanation:</u>

1) 10, 2, 1.2, 1.12, 1.112, 1.1112

t_n=\dfrac{t_{n-1}}{10}+1

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t₃ = 2/10 + 1     = 1.2

t₄ = 1.2/10 + 1   = 1.12

t₅ = 1.12/10 + 1  = 1.112

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2)  10, 2, -2, -4, -5, -5.5, ...

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t₁ = 10

t₂ = 10/2 - 3 =   2

t₃ = 2/2 - 3  =  -2

t₄ = -2/2 - 3 =  -4

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8 0
3 years ago
What should you multiply the top equation by so that y is eliminated when the
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Your answer is D. 2 :)
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3 years ago
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What two numbers multiply to 54 and add up to 7
k0ka [10]
Xy = 54
x + y = 7

xy = 54
\frac{xy}{x} = \frac{54}{x}
y = \frac{54}{x}

x + y = 7
x + \frac{54}{x} = 7
\frac{x^{2}}{x} + \frac{54}{x} = 7
\frac{x^{2} + 54}{x} = 7
x^{2} + 54 = 7x
x^{2} - 7x + 54 = 0
x = \frac{-(-7) \± \sqrt{(-7)^{2} - 4(1)(54)}}{2(1)}
x = \frac{7 \± \sqrt{49 - 216}}{2}
x = \frac{7 \± \sqrt{-167}}{2}
x = \frac{7 \± i\sqrt{167}}{2}
x = \frac{7 \± 12.9i}{2}
x = 3.5 \± 6.45i
x = 3.5 + 6.45i    or    3.5 - 6.45i

                  x + y = 7
   3.5 + 6.45i + y = 7
- (3.5 + 6.45i)       - (3.5 + 6.45i)
                        y = 3.5 - 6.45i
                  (x, y) = (3.5 + 6.45i, (3.5 - 6.45i)

                          or

                  x + y = 7
   3.5 - 6.45i + y = 7
- (3.5 - 6.45i)     - (3.5 - 6.45i)
                       y = 3.5 + 6.45i
                 (x, y) = (3.5 - 6.45i, 3.5 + 6.45i)

The two numbers that add up to 7 and can multiply to 54 is 3.5 ± 6.45i.
5 0
3 years ago
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