The answer is -7+19i because of the procedure used in math
Answer:
A(t) = 300 -260e^(-t/50)
Step-by-step explanation:
The rate of change of A(t) is ...
A'(t) = 6 -6/300·A(t)
Rewriting, we have ...
A'(t) +(1/50)A(t) = 6
This has solution ...
A(t) = p + qe^-(t/50)
We need to find the values of p and q. Using the differential equation, we ahve ...
A'(t) = -q/50e^-(t/50) = 6 - (p +qe^-(t/50))/50
0 = 6 -p/50
p = 300
From the initial condition, ...
A(0) = 300 +q = 40
q = -260
So, the complete solution is ...
A(t) = 300 -260e^(-t/50)
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The salt in the tank increases in exponentially decaying fashion from 40 grams to 300 grams with a time constant of 50 minutes.
Answer:
306
Step-by-step explanation:
mark brainliest :)
Answer:
The answer to your question is Long = 10.39
Step-by-step explanation:
Data
hypotenuse = 12
long = ?
Process
1.- To find Long, we must use the trigonometric functions sine or cosine.
If we use sine, we use the 60° angle
If we use cosine, we use the 30° angle
a) sin 60 = long / hypotenuse
Long = hypotenuse x sin 60
Long = 12 x sin 60
Long = 10.39
b) cos 30 = Long / hypotenuse
Long = hypotenuse x cos 30
Long = 12 x cos 30
Long = 10.39
