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Mashutka [201]
3 years ago
14

at party the pumpkin pie is cut into 14 slices and the cherry pies cut into seven slices if the host wants to serve identical pl

ates that contained the same combination of pumpkin and Cherry sizes with no slices leftover what is the greatest number of plates the host can prepare
Mathematics
1 answer:
Lyrx [107]3 years ago
7 0

Answer:

The host can only prepare 7 plates

Step-by-step explanation:

7 plates, each will contain 1 slice of cherry pie and 2 slices of pumpkin pie. (14/7 = 2)

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Line M is represented by the following equation: x − y = 8
PIT_PIT [208]
Let's plug in (18,10) into each answer choice until we find the one that has it as a solution.

A) 2x - y = 26
2(18) - 10 = 26
36 - 10 = 26
26 = 26

Your answer is A.

I'll just do the rest to show that you the they are incorrect.

B) x + y = 18
18 + 10 = 18
28 ≠ 18

C) 2x - 2y = 36
2(18) - 2(10) = 36
36 - 20 = 36
16 ≠ 36

D) x - y = -28
18 - 10 = -28
8 ≠ -28


Your answer is A) 2x - y = 26.
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3 years ago
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aleksklad [387]

Answer:

B) 454.50

Step-by-step explanation:

-25.50 + 480.00 = 454.50

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What's 32.88 divided by 0.6​
otez555 [7]
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For 20 points and brainliest
Korvikt [17]

Answer:

376.99in³

Step-by-step explanation:

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A vertical cylinder is leaking water at a rate of 4m3/sec. If the cylinder has a height of 10m and a radius of 2m, at what rate
Lyrx [107]

Answer:

Therefore the rate change of height is  \frac{1}{\pi} m/s.

Step-by-step explanation:

Given that a vertical cylinder is leaking water at rate of 4 m³/s.

It means the rate change of volume is 4 m³/s.

\frac{dV}{dt}=4 \ m^3/s

The radius of the cylinder remains constant with respect to time, but the height of the water label changes with respect to time.

The height of the cylinder be h(say).

The volume of a cylinder is V=\pi r^2 h

                                                 =( \pi \times 2^2\times h)\ m^3

\therefore V= 4\pi h

Differentiating with respect to t.

\frac{dV}{dt}=4\pi \frac{dh}{dt}

Putting the value \frac{dV}{dt}

\Rightarrow 4\pi \frac{dh}{dt}=4

\Rightarrow \frac{dh}{dt}=\frac{4}{4\pi}

\Rightarrow \frac{dh}{dt}=\frac{1}{\pi}

The rate change of height does not depend on the height.

Therefore the rate change of height is  \frac{1}{\pi} m/s.

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