Answer:
By AA
ΔWXY ~ΔWVZ
Step-by-step explanation:
Here WXY is an isosceles triangle with legs WX & WY
So WX = WY
Hence ∠X = ∠Y
So ∠2= ∠3.
Now by angle sum property
∠1 + ∠2+∠3 = 180°
∠1+∠2+∠2=180°
2∠2 = 180° - ∠1 .......(1)
In triangle WVZ
WV = WZ
So ∠V = ∠Z
∠4 = ∠5
Once again by angle sum property
∠1 + ∠4 + ∠5=180°
∠1 + ∠4 + ∠4 = 180°
2∠4 = 180° - ∠1 ...(2)
From (1) & (2)
2∠2 = 2∠4
∠2=∠4
Now ∠W is common to both triangles
Hence by AA
ΔWXY ~ΔWVZ
Step-by-step explanation:
Starting from y-intercept of [0, 2], you can either move two blocks <em>north</em><em> </em>over 3 blocks <em>west</em><em> </em>or two blocks <em>south</em><em> </em>over three blocks <em>east</em><em>.</em><em> </em>Either way, you will still get this line because this is a negative <em>rate</em><em> </em><em>of</em><em> </em><em>change</em><em> </em>[<em>slope</em>].
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**I have a video that explains something like this. It is titled "Finding Slopes, y-intercepts, Perpendicular Equations, and Parallel Equations". I encourage you to watch the video and gain alot more knowledge from it, so you can better understand the concepts.
