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Citrus2011 [14]
3 years ago
5

Find the Unit Rate

Mathematics
2 answers:
andre [41]3 years ago
7 0

Answer:

22

Step-by-step explanation:

88 divided by 4 is 22.

kirill [66]3 years ago
6 0

Answer:

22

Step-by-step explanation:

give them brain, they're correct.

You might be interested in
What is the term to term rule for this sequence 64 32 16 8 4
nikklg [1K]

Answer:

Divide by 2 each time.

Step-by-step explanation:

The rule is dividing by 2 each time.

64/2=32

32/2=16

16/2=8

8/2=4

Hope this helps you!! Have an amazing day, and happy thanksgiving ^^

4 0
3 years ago
Use the Divergence Theorem to evaluate S F · dS, where F(x, y, z) = z2xi + y3 3 + tan z j + (x2z + y2)k and S is the top half of
Romashka-Z-Leto [24]
By the divergence theorem, the surface integral over S_2 is

\displaystyle\iint_{S_2}\mathbf F\cdot\mathrm dS=\iiint_R\nabla\cdot\mathbf F\,\mathrm dR

where R denotes the space bounded by S_2. Assuming the vector field is given to be

\mathbf F(x,y,z)=z^2x\,\mathbf i+(y^3+\tan z)\,\mathbf j+(x^2z+y^2)\,\mathbf k

then

\nabla\cdot\mathbf F=\dfrac\partial{\partial x}[z^2x]+\dfrac\partial{\partial y}[y^3+\tan z]+\dfrac\partial{\partial z}[x^2z+y^2]=z^2+3y^2+x^2

Converting to spherical coordinates, we take

\begin{cases}x=\rho\cos\theta\sin\varphi\\y=\rho\sin\theta\sin\varphi\\z=\rho\cos\varphi\end{cases}

so that the triple integral becomes

\displaystyle\int_{\varphi=0}^{\varphi=\pi/2}\int_{\theta=0}^{\theta=2\pi}\int_{\rho=0}^{\rho=3}(\rho^2\cos^2\varphi+3\rho^2\sin^2\theta\sin^2\varphi+\rho^2\cos^2\theta\sin^2\varphi)\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi
=\displaystyle\int_0^{\pi/2}\int_0^{2\pi}\int_0^3\rho^4(\cos^2\varphi+2\sin^2\theta\sin^2\varphi+\sin^2\varphi)\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi
=162\pi

Now the integral over S alone will be the difference of the integral over S_2 and the integral over S_1, i.e.

\displaystyle\iint_{S_2}=\iint_{S_1\cup S}=\iint_{S_1}+\iint_S\implies\iint_S=\iint_{S_2}-\iint_{S_1}

We can parameterize the points in S_1 by

\mathbf s(r,\theta)=\begin{cases}x=r\cos\theta\\y=r\sin\theta\\z=0\end{cases}

so that the integral over S_1 is

\displaystyle\iint_{S_1}\mathbf F\cdot\mathrm dS=\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=3}\mathbf F(x(r,\theta),y(r,\theta),z(r,\theta))\cdot\left(\dfrac{\partial\mathbf s}{\partial r}\times\dfrac{\partial\mathbf s}{\partial\theta}\right)\,\mathrm dr\,\mathrm d\theta
=\displaystyle\int_0^{2\pi}\int_0^3(r^3\sin^3\theta\,\mathbf j+r^2\sin^2\theta\,\mathbf k)\cdot(r\,\mathbf k)\,\mathrm dr\,\mathrm d\theta
=\displaystyle\int_0^{2\pi}\int_0^3r^3\sin^2\theta\,\mathrm dr\,\mathrm d\theta
=\dfrac{81\pi}4

So, the integral over S alone evaluates to

\displaystyle\iint_S=\iint_{S_2}-\iint_{S_1}=162\pi-\dfrac{81\pi}4=\dfrac{567\pi}4
3 0
3 years ago
20% of 40? Please help my friend and I got different answers!
Ipatiy [6.2K]
20% of 40 is 8 

Hope this helps! :D
8 0
3 years ago
Read 2 more answers
Lin-Yao spent a titl of 12.5 minutes folding some paper origami cranes. it took her 1.25 minutes to fold each one. The equation
Brilliant_brown [7]
1.25c=12.5
Let's look at the equation. We need C by itself. The only way we can do so is by dividing each side by 1.25
1.25c=12.5
1.25c÷1.25= c
12.5÷1.25= 10
C=10
The value of C in the equation is 10.
8 0
4 years ago
0.25 and 1/8 closets to 0,1,2 or 3
s2008m [1.1K]
Not sure what you are asking but 0.25 and 1/8 are closer to 1 than they are 2
7 0
4 years ago
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