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2 years ago

Pls help 50 points

Mathematics

2 answers:

baherus [9]2 years ago

7 0

$\bf \underline{ \underline{Given : }}$

Width = 3√2 inches

Length = 4√2 inches

$\bf \underline{ \underline{To \: Find \: Out:}}$

Find the area of given rectangle.

$\bf \underline{ \underline{Solution:}}$

As we know that,

Area of rectangle = Length × Width

$\rightarrow \: 4 \sqrt{2} \times 3 \sqrt{2}$

$\rightarrow \: 12 (\sqrt{2}) {}^{2}$

$\rightarrow \: 12 \times 2$

$\rightarrow \boxed{24 \: sq. \: inches}$

Ostrovityanka [42]2 years ago

6 0

Answer:

24 in²

Step-by-step explanation:

Given:

w = 3√2 in
l = 4√2 in

Area is:

A = wl
A = 3√2*4√2 = 12*2 = 24 in²

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$\huge\quad\qquad\underline{{\sf Answer}}$

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thus the distances connecting the opposite entrances can be calculated as follows:

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