4 = y - 4 <br> 3 = 9 - y<br> 1 = 8 - y<br> 2 = 9 - y<br> 4 = y

a slitter assembly contains 48 blades five blades are selected at random and evaluated each day for sharpness if any dull blade

son4ous [18]

Answer:

P(at least 1 dull blade)=0.7068

Step-by-step explanation:

I hope this helps.

This is what it's called dependent event probability, with the added condition that at least 1 out of 5 blades picked is dull, because from your selection of 5, you only need one defective to decide on replacing all.

So if you look at this from another perspective, you have only one event that makes it so you don't change the blades: that 5 out 5 blades picked are sharp. You also know that the probability of changing the blades plus the probability of not changing them is equal to 100%, because that involves all the events possible.

P(at least 1 dull blade out of 5)+Probability(no dull blades out of 5)=1

P(at least 1 dull blade)=1-P(no dull blades)

But the event of picking one blade is dependent of the previous picking, meaning there is no chance of picking the same blade twice.

So you have 38/48 on getting a sharp one on your first pick, then 37/47 (since you remove 1 sharp from the possibilities, and 1 from the whole lot), and so on.

Also since are consecutive events, you need to multiply the events.

The probability that the assembly is replaced the first day is:

P(at least 1 dull blade)=1-P(no dull blades)

$P(at least 1 dull blade)=1-(\frac{38}{48}* \frac{37}{47} *\frac{36}{46}*\frac{35}{45}*\frac{34}{44})$

$P(at least 1 dull blade)=1-0.2931$

P(at least 1 dull blade)=0.7068

5 0

3 years ago

HELPPP MEEEE PLEASE!

Nataly [62]

Answer:

What is that

Step-by-step explanation:

I am scared of math

6 0

3 years ago

Provide the reflected ordered pair for each of the given ordered pairs. Reflect the ordered pair ( − 4 , 5 ) (-4, 5) across the

levacccp [35]

Answer:

a) (4,5)

b) (0,-3)

Step-by-step explanation:

We have to perform the following reflection over given ordered pair.

a) Reflect the ordered pair (-4,5) across the y-axis

Reflection over y-axis:

$r: (x,y)\rightarrow (-x,y)$

Thus, (-4,5) will be reflected over y-axis as

$r: (-4,5)\rightarrow (-(-4),5) = (4.5)$

b) Reflect the ordered pair (0,3) across the y-axis

Reflection over x-axis:

$r: (x,y)\rightarrow (x,-y)$

Thus, (0,3) will be reflected over x-axis as

$r: (0,3)\rightarrow (0,-(3)) = (0,-3)$

6 0

3 years ago

In one area, monthly incomes of technology-related workers have a standard deviation of $650. It is believed that the standard d

Virty [35]

Answer:

There is sufficient statistical evidence to prove that the standard deviation of the technology-related workers and the standard deviation of the non-technology workers are equal.

Step-by-step explanation:

Here we have our null hypothesis as H₀: σ² = s²

Our alternative hypothesis is then Hₐ: σ² ≠ s²

We therefore have a two tailed test

To test the hypothesis of difference in standard deviation which is the Chi squared test given as follows

$\chi ^{2} = \dfrac{\left (n-1 \right )s^{2}}{\sigma ^{2}}$

Where:

n = Size of sample

s² = Variance of sample = 950²

σ² = Variance of population = 650²

Degrees of freedom = n - 1 = 71 - 1 = 70

α = Significance level = 0.1

Therefore, we use 1 - 0.1 = 0.9

From the Chi-square table, we have the critical value as

1 - α/2 = 51.739,

α/2 = 90.531

Plugging the values in the above Chi squared test equation, we have;

$\chi ^{2} = \dfrac{\left (23-1 \right )950^{2}}{650 ^{2}} = 49.994$

Therefore, since the test value within the critical region, we do not reject the null hypothesis, hence there is sufficient statistical evidence to prove that the standard deviation of the technology-related workers and the standard deviation of the non-technology workers are equal.

6 0

2 years ago

Graph the parabola. y= - 5over2 X^2 -20x -35 plot the vertex and four additional points, two on each side of the vertex. Then cl

stich3 [128]

Wheres the graph ;/ or an link or image

8 0

3 years ago

4 = y - 4 3 = 9 - y 1 = 8 - y 2 = 9 - y 4 = y - 3