The equation relating length to width
L = 3W
The inequality stating the boundaries of the perimeter
LW <= 112
When you plug in what L equals in the first equation into the second equation, you get
3W * W <= 112
evaluate
3W^2 <= 112
3W <=
W <=
cm
Answer:
-1
Step-by-step explanation:
dy/dt = y² − 1 = (y + 1) (y − 1)
At t = 0, y = 0, and dy/dt = -1. Therefore, y is initially decreasing.
As y decreases, dy/dt increases. When y = -1, dy/dt = 0 and changes signs from negative to positive.
As y increases above -1, dy/dt again becomes negative. So y continues to approach -1 as t approaches infinity.
#1. B
<span>(z * z^2 + z * 2z + z * 4) – (-2 *z^2 – (-2) 2z – (-2) 4)
Z^3 + 2z^2 + 4z – 2z^2 -4z – 8
Z^3 + 2z^2 – 2z^2 + 4z – 4z – 8
Z^3 - 8
</span>
#2 and #3. D
<span>(x + y)(x + 2)
x^2 + 2x + yx + 2y
</span>
#4. D.
<span>(x - 7)(x + 7)(x- 2)
x^2 + 7x – 7x -49
x^2 + x – 49
x^2 -49
(x^2 – 49 ) (x – 2)
x^3 – 2x^2 – 49x + 98
</span>
#5. C
(y - 4) = 0
y = 4
(x + 3)= 0
x = -3
#6. A and B
45 i guessStep-by-step explanation:
