The answer
the complement of the question is
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Find the interval on the real number line for which the radicand is nonnegative (greater than or equal to zero)</span><span> so that the radical sqrt(8 x - 8) defines a real number. Leave answer in interval notation.
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sqrt(8 x - 8) is definite function if <span>8 x - 8 ≥0, </span>
8 x <span><span> ≥ 8</span> and x </span>≥ 8/ 8 = 1, x <span>≥ 1, so the interval solution is [1, infinity[</span>
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Answer:
to the nearest whole degree means that you look at the first decimal place. if it is less than 5, you keep the whole number and eliminate the decimal. if otherwise, the decimal is ≥5, you round up the whole number and eliminate the decimal.
Hi. Your answer is 5,700 because 685 is closer to 700 than 600. Please ask if you have any more questions. Also please mark as the brainliest answer!
Answer: 225
Step-by-step explanation:
For this case we must find the inverse of the following function:
We follow the steps below:
Replace f(x) with y:
We exchange the variables:
We solve for "y":
Multiply by -2 on both sides of the equation:
We raise both sides of the equation to the square to eliminate the radical:
We subtract 3 from both sides of the equation:
We change y by f ^ {- 1} (x):
Answer:
