To solve this problem you must follow the proccedure shown below:
1. You have that <span>the pasture must contain 128 square meters and no fencing is required along the river. Then:
A=LxW
A is the area
L is the lenght
W is the width
2. Let's clear W:
W=A/L
W=128/L
3. The formula of the perimeter is:
P=2L+W
P=2L+(128/L)
4. Now, you must derivate:
dP/dL=0
2+(128/L</span>²)=0
<span> L=8 meters
W=A/L
W=128/8
W=16 meters
</span>
Answer:
Prime factorization: 99 = 3 x 3 x 11, which can also be written 99 = 3² x 11
Step-by-step explanation: HOPE THIS HELPS
99 = 3 x 3 x 11, which can also be written 99 = 3² x 11.
Step-by-step explanation:
(g+f)(x) ie option B
-2+1 = -1
1-2 = -1
4-5 = - 1
An easy way is since there are 2 big numbers and 1 small, add the small to the larger
let's add it to the third number
1,000+2,832,783,920=2,832,784,920
now add 20,029,293,848,493 to 2,832,784,920 (use calculator)
basically you add up the1's place with the 1's place, 10's place with the 10's place and so on
1's=3+0=3
10's=9+2=11 or 1 and move 1 up to next place
100's=4+9+1=14 or 4 and move 1 up to next place
1,000's= 8+4+1=13 or 3 and move 1 up to next place
10,000's= 4+8+1=13 or 3 and move 1 up to next place
100,000's= 8+7+1=16 or 6 and move 1 up to next place
1,000,000's= 3+2+1=6
10,000,000= 9+3=12 or 2 and move 1 up to next place
100,000,000=2+8+1=11 or 1 and move 1 up to next place
1,000,000,000= 9+2+1=12 or 2 and move 1 up to next place
therer are no more number on the smaller number so just add the bigger ones at the top with the added 1 so
20,032,126,633,413
Answer:
The critical value for a 98% CI is z=2.33.
The 98% confidence interval for the mean is (187.76, 194.84).
Step-by-step explanation:
We have to develop a 98% confidence interval for the mean number of minutes per day that children between the age of 6 and 18 spend watching television per day.
We know the standard deveiation of the population (σ=21.5 min.).
The sample mean is 191.3 minutes, with a sample size n=200.
The z-value for a 98% CI is z=2.33, from the table of the standard normal distribution.
The margin of error is:
With this margin of error, we can calculate the lower and upper bounds of the CI:
The 98% confidence interval for the mean is (187.76, 194.84).
