In order to find the slope of line that passes through 2 points, use the equation slope=rise/run
rise = 5-(-4) =9
run = 2- 0 =2
slope = rise/run = 9/2
Given:
Tangent segment MN = 6
External segment NQ = 4
Secant segment NP =x + 4
To find:
The length of line segment PQ.
Solution:
Property of tangent and secant segment:
If a secant and a tangent intersect outside a circle, then the product of the secant segment and external segment is equal to the product of the tangent segment.
Subtract 16 from both sides.
Divide by 4 on both sides.
The length of line segment PQ is 5 units.
VR // TS is true,
as when reflected image is translated by 2 unit right than it will make it rectangle
hope it helped
Answer: (fg)(x) = 6x^2 + 11x - 7
Explanation:
(2x - 1)(3x + 7)
= 6x^2 + 14x -3x -7
= 6x^2 + 11x - 7
Answer:
20,667.
Step-by-step explanation:
This is an arithmetic series:
3 + 9 + 15 + 21 + 27+ ...........+ 495
First term = 3 and common difference = 6.
Number of terms = ( 495 - 3 )/6 + 1
= 83.
So Sn = n/2(a1 + l) where a1 = first term and l = last term
S83 = 83/2(3 + 495)
= 41.5 * 498
= 20,667.
