Let
x---------> first positive integer
x+1------> second positive integer
x+2-----> third positive integer
we know that
(x+1)*(x+2)=72-------> x² +2x+x+2=72 -------> x² +3x-70=0
using a graph tool-------> <span>I solve the quadratic equation
</span>see the attached figure
the roots are
x1=-10
x2=7
the answer is
first positive integer is x=7
second positive integer is x+1=8
third positive integer is x+2=9
So.. if we take the numerator to be say "a", then the denominator will be "a+3"

either of those two fractions will do
Answer:
Hiiiii
I'm okay, how about you?
thanks for the free points! :)
Answer:
(1,-4) is in quadrant IV.
Step-by-step explanation:
Answer: OPTION B
Step-by-step explanation:
You can observe that the exercise provides you two Linear functions.
The first Linear function is the function f(x). This is:

And the other Linear function is the function g(x):

In order to find
, you need to follow these steps shown below:
<u>Step 1</u>:
You must substitute the function f(x) into the function g(x); this means that the function f(x) will be in the place of the variable "x" of the function g(x); as you can observe below:

<u>Step 2</u>:
Finally you must combine the like terms (You can notice that the like terms are 1 and 14; then you must add them). Therefore, you get that
is:
