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2 years ago

What is the slope of the line in the graph?

Mathematics

1 answer:

Dominik [7]2 years ago

3 0

The slope of this line is positive

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Joey cut a 10.5 foot length rope into 6 pieces of equal length. How long was each piece?

Scorpion4ik [409]

1.75 feet each.
6* 1.75= 10.5

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3 years ago

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Write an expression that shows how to multiply 7 x 256 using expanded form and the distributive property

natali 33 [55]

256×7=1792 in expanded form it is 1000+700+90+2

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3 years ago

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20. An amount of money was shared among five boys Ali, Juma, Musa, Khalid and Mustafa. Ali got /8 of the total amount while Juma

Nadusha1986 [10]

Answer:

$x=\frac{18000}{7}=2571\frac{3}{7}$

Step-by-step explanation:

Let the total amount be x

Then Ali got 1/8x With 7/8x left

Juma got 7/40x with 7/10x left

Musa, Khalid and Mustafa got 7/30x each

since $\frac{7}{30}x=600$

7x=18000

$x=\frac{18000}{7}=2571\frac{3}{7}$

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1 year ago

The lovin lemon company sells a 4 gallon jug of lemonade for $24 the sweet and sour company sells an 8 pack of 1 quart bottles o

Angelina_Jolie [31]

The 8 pack of 1 quart bottles of lemonade is the higher price unit because 4 gallons equal 16 quarts. 16 divided by 2= 8 and 24 divided by 2 =12 dollars. so therefore 8 quarts of "lovin lemon" company is $12 and 8 quarts of "sweet and sour" company is $16 so THE ANSWER IS: "SWEET AND SOUR" COMPANY HAS THE HIGHER UNIT RATE.

5 0

3 years ago

The angle θ 1 is located in Quadrant IV, and cos ⁡ ( θ 1 ) = 9/ 19 , theta, start subscript, 1, end subscript, right parenthesis

Firdavs [7]

Answer:

$sin\theta_1 = - \frac{2\sqrt{70}}{19}$

Step-by-step explanation:

We are given that $\theta_1$ is in fourth quadrant.

$cos\theta_1$ is always positive in 4th quadrant and

$sin\theta_1$ is always negative in 4th quadrant.

Also, we know the following identity about $sin\theta$ and $cos\theta$ :

$sin^2\theta + cos^2\theta = 1$

Using \theta_1 in place of \theta:

$sin^2\theta_1 + cos^2\theta_1 = 1$

We are given that $cos\theta_1 = \frac{9}{19}$

$\Rightarrow sin^2\theta_1 + \dfrac{9^2}{19^2} = 1\\\Rightarrow sin^2\theta_1 = 1 - \dfrac{81}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{361-81}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{280}{361}\\\Rightarrow sin\theta_1 = \sqrt{\dfrac{280}{361}}\\\Rightarrow sin\theta_1 = +\dfrac{2\sqrt{70}}{19}, -\dfrac{2\sqrt{70}}{19}$

$\theta_1$ is in 4th quadrant so $sin\theta_1$ is negative.

So, value of $sin\theta_1 = - \frac{2\sqrt{70}}{19}$

6 0

2 years ago