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Masja [62]
3 years ago
5

The diagram below shows the percentages of people attending a football game who were supporters of either the home team or the v

isiting team.
Mathematics
2 answers:
Yuliya22 [10]3 years ago
4 0
Can you show a picture of the diagram
Airida [17]3 years ago
3 0
Visiting team 20%, home team 80%
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Is it possible for a pair of nonadjacent angles to share a vertex ?
Hoochie [10]
Yes with vertical Angles.
:) hope this helps
3 0
3 years ago
Find the exact value of each expression, if it defined. ( if answer is undefined, enter undefined) tan (-1)
Triss [41]

Answer:

tan(-1) \approx -0.02

Step-by-step explanation:

The given expression is

tan(-1)

The tangent of -1 is defined, it's around -0.02.

The tangent is a trigonometric function with a period of \pi, where each period is separated by a vertical asymptote which indicates that the function is not determined through all its domain, that's what the question refers to when it says "if is undefined, enter undefined".

However, at x=-1, the tangent is determined, that means, there's no asymptote on that coordinate, that's why it has a "determined value", which is -0.02 approximately.

tan(-1) \approx -0.02

6 0
3 years ago
A volleyball reaches its maximum of 13 feet, 3 seconds after it is served. What quadratic formula could model the height of the
Katena32 [7]

Answer:

H=-(t-3)^2+13

Step-by-step explanation:

The path covered by the volleyball will be a downward parabola with the vertex being the highest point of the ball.

A general form of a downward parabola is given as:

y=-a(x-h)^2+k

Where (h,k) is the vertex of the parabola and 'a' is a constant.

Now, let 'h' be the vertical height and 't' be the time taken.

So, the equation would be of the form:

H=-a(t-h)^2+k

Now, as per question:

h = 2 seconds, k = 13 feet.

H=-a(t-3)^2+13

Now, taking a = 1. So, the formula that can be used is:

H=-(t-3)^2+13

7 0
3 years ago
Integration of the following function
DerKrebs [107]

Answer: None of the above

Step-by-step explanation:

Given

\frac{\mathrm{d} \bar{c}}{\mathrm{d} x}=-6x^{-2}+\frac{1}{6}

d\bar{c}=\left (  -6x^{-2}+\frac{1}{6}\right )dx

Now, integrating both sides

\int d\bar{c}=\int \left (  -6x^{-2}+\frac{1}{6}\right )dx

\bar{c}=-6\frac{x^{-2+1}}{-2+1}+\frac{1}{6}x+k_1

\bar{c}=6x^{-1}+\frac{1}{6}x+k_1

6 0
3 years ago
3.01(the 1 is repeating)as a mixed number
Masteriza [31]
The quick and easy answer is 3/100
7 0
3 years ago
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