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skad [1K]
3 years ago
5

Students are planning a 3 day hiking trip in the mountains. The hike covers a distance of 18.5 kilometers. The students hike 0.2

8 of the total distance the first day. If they split the remaining distance equally between the second and third days how far will they hike on day three?
Mathematics
2 answers:
11Alexandr11 [23.1K]3 years ago
8 0

Answer:

They hike 9.11 km on day three

Step-by-step explanation:

Total distance traveled on a 3 day hiking trip in the mountains = 18.5 km

The students hike 0.28 of the total distance the first day.

So, Remaining distance = 18.5 - 0.28 = 18.22

Now we are given that they split the remaining distance equally between the second and third days

So, Distance traveled by them on third = Distance traveled by them on second day = Half of the remaining distance = \frac{18.22}{2} = 9.11

So, they hike 9.11 km on day three

Fudgin [204]3 years ago
3 0
The students will hike 9.11 KM on day three.
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3 years ago
An appliance manufacturer claims to have developed a compact microwave oven that consumes a mean of no more than 250 W. From pre
melamori03 [73]

Answer:

We conclude that a compact microwave oven consumes a mean of more than 250 W.

Step-by-step explanation:

We are given that an appliance manufacturer claims to have developed a compact microwave oven that consumes a mean of no more than 250 W with a population standard deviation of 15 W.

They take a sample of 20 microwave ovens and find that they consume a mean of 257.3 W.

Let \mu = <u><em>mean power consumption for microwave ovens.</em></u>

So, Null Hypothesis, H_0 : \mu \leq 250 W     {means that a compact microwave oven consumes a mean of no more than 250 W}

Alternate Hypothesis, H_A : \mu > 250 W     {means that a compact microwave oven consumes a mean of more than 250 W}

The test statistics that would be used here <u>One-sample z test statistics</u> as we know about the population standard deviation;

                                T.S. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean power consumption for ovens = 257.3 W

            σ = population standard deviation = 15 W

            n = sample of microwave ovens = 20

So, <em><u>the test statistics</u></em>  =  \frac{257.3-250}{\frac{15}{\sqrt{20} } }

                                      =  2.176

The value of z test statistics is 2.176.

<u>Now, at 0.05 significance level the z table gives critical value of 1.645 for right-tailed test.</u>

Since our test statistic is more than the critical value of t as 2.176 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that a compact microwave oven consumes a mean of more than 250 W.

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Answer:

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